y=m^2+3-2x+1+mx
y=x(x+1)-(m-1)^2
y=(m-1)x + 2m+3x
y=x(x+1)-2mx-x^2+3m
y=m^2x^2 -x(x-1) +mx-z
y=m^2+3-2x+1+mx y=x(x+1)-(m-1)^2 y=(m-1)x + 2m+3x y=x(x+1)-2mx-x^2+3m y=m^2x^2 -x(x-1) +mx-z
By Quinn
By Quinn
y=m^2+3-2x+1+mx
y=x(x+1)-(m-1)^2
y=(m-1)x + 2m+3x
y=x(x+1)-2mx-x^2+3m
y=m^2x^2 -x(x-1) +mx-z
Đáp án:
Giải thích các bước giải:
y = 100
y=2%
y=2k
y=lol
y=JQK