1) -1/12 – (2′ 5/8 – 1/3). Là hai, năm phần tám. 2) -1/75 – (-1/9 – 2′ 1/18) 3) -5/6 – (-3/8 + 1/10) 4) 2/5 + (-4/3) + (-1/2) 5) 3/12 – (6/15 – 3/10)

1) -1/12 – (2′ 5/8 – 1/3). Là hai, năm phần tám.
2) -1/75 – (-1/9 – 2′ 1/18)
3) -5/6 – (-3/8 + 1/10)
4) 2/5 + (-4/3) + (-1/2)
5) 3/12 – (6/15 – 3/10)
6) 2^15.9^4/6^6.8^3

0 bình luận về “1) -1/12 – (2′ 5/8 – 1/3). Là hai, năm phần tám. 2) -1/75 – (-1/9 – 2′ 1/18) 3) -5/6 – (-3/8 + 1/10) 4) 2/5 + (-4/3) + (-1/2) 5) 3/12 – (6/15 – 3/10)”

  1. Đáp án:

    `1) -1/12 – (2 (5)/8 – 1/3)`

    `= -1/12 – (55)/24`

    `= -19/8`

    `2) -1/75 – (-1/9 – 2(1)/18)`

    `= -1/75 + 13/6`

    `= (323)/150`

    `3) -5/6 – (-3/8 + 1/10)`

    `= -5/6 + 11/40`

    `= -67/120`

    `4) 2/5 + (-4/3) + (-1/2)`

    `= -14/15 + -1/2`

    `= -43/30`

    `5) 3/12 – (6/15 – 3/10)`

    `= 3/12 – 1/10`

    `= 3/20`

    `6) (2^15 . 9^4)/(6^6 . 8^3)`

    `=` $\frac{2^{15}.3^{8} }{2^{6}.3^{6}.2^{9} }$ 

    `= 3^2 = 9`

    Học tốt !

    Bình luận
  2. 1) $-\dfrac{1}{2}-(2\dfrac{5}{8}-\dfrac{1}{3})$

    $=-\dfrac{1}{2}-\dfrac{21}{8}+\dfrac{1}{3}$

    $=-\dfrac{12}{24}-\dfrac{63}{24}+\dfrac{8}{24}=-\dfrac{43}{24}$

    2) $-\dfrac{1}{75}-(-\dfrac{1}{9}-2\dfrac{1}{18})$

    $=-\dfrac{1}{75}-(-\dfrac{2}{18}-\dfrac{37}{18})$

    $=-\dfrac{1}{75}+\dfrac{13}{6}=\dfrac{109}{50}$

    3) $-\dfrac{5}{6}-(-\dfrac{3}{8}+\dfrac{1}{10})$

    $=-\dfrac{5}{6}+\dfrac{3}{8}+\dfrac{1}{10}$

    $=-\dfrac{11}{24}+\dfrac{1}{10}=-\dfrac{110}{240}+\dfrac{24}{240}=-\dfrac{43}{120}$

    4) $\dfrac{2}{5}+(-\dfrac{4}{3})+(-\dfrac{1}{2})$

    $=\dfrac{2}{5}-\dfrac{4}{3}-\dfrac{1}{2}$

    $=\dfrac{12}{30}-\dfrac{40}{30}-\dfrac{15}{30}=-\dfrac{43}{30}$

    5) $\dfrac{3}{12}-(\dfrac{6}{15}-\dfrac{3}{10})$

    $=\dfrac{3}{12}-\dfrac{1}{10}$

    $=\dfrac{30}{120}-\dfrac{12}{120}=\dfrac{3}{20}$

    6) $\dfrac{2^{15}.9^4}{6^6.8^3}=\dfrac{(2^3)^5.9^4}{(6^2)^3.8^3}$

    $=\dfrac{8^5.9^4}{8^3.36^3}=\dfrac{8^5}{8^3}.\dfrac{9^4}{36^3}$

    $=8^2.\dfrac{9}{64}=64.\dfrac{9}{64}=9$

     

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