1, 1/2x-1 + 3/12x-8=2/3x-2 2, 3/x+3 – 1/x-2=5/2x+6 3, 4/x-2 + x/x+1=x^2-2/x^2-x-2 4, x/x^2-1 + 3/x^2-2x-3=x/x^2-4x+3

0 bình luận về “1, 1/2x-1 + 3/12x-8=2/3x-2 2, 3/x+3 – 1/x-2=5/2x+6 3, 4/x-2 + x/x+1=x^2-2/x^2-x-2 4, x/x^2-1 + 3/x^2-2x-3=x/x^2-4x+3”

1. 1,1/2x-1+3/12x-8=2/3x-2

   =1/2x-1 +3/4(3x-2)=2/3x-2

   =1.4(3x-2)+3.(2x-1)/4.(3x-2)(2x-1)=2.4.(2x-1)/4.(3x-2)(2x-1)

   =12x-8+6x-3=16x-8

   =x=3

   2,3/x+3-1/2x-1=5/2x+6

   = 3/x+3-1/x-2=5/2(x+3)

   =3.2.(x-2)-1.2.(x+3)/2.(x+3)(x-2)=5.(x-2)/2.(x+3)(x-2)

   =6x-12-2-6x=5x-10

   =-5x=4

   =x=-4/5

   3,4/x-2+x/x+1=x^2-2/x^2-4x+3

   =4(x+1)+x(x-2)/(x+1)(x-2)=x^2/(x+1)(x-2)

   =4x+4+x^2-2x=x^2

   =x=-2

   Giải thích các bước giải:

    

   Trả lời

2. `1, 1/2x-1+3/12x-8=2/3x-2`

   `=1/2x-1 +3/4(3x-2)=2/3x-2`

   `=1.4(3x-2)+3.(2x-1)/4.(3x-2)(2x-1)=2.4.(2x-1)/4.(3x-2)(2x-1)`

   `=12x-8+6x-3=16x-8`

   `x=3`

   `2, 3/x+3-1/2x-1=5/2x+6`

   `= 3/x+3-1/x-2=5/2(x+3)`

   `= 3.2.(x-2)-1.2.(x+3)/2.(x+3)(x-2)=5.(x-2)/2.(x+3)(x-2)`

    `= 6x-12-2-6x=5x-10`

   `=-5x = 4`

   `=x=-4/5`

   `3, 4/x-2+x/x+1=x^2-2/x^2-4x+3`

   `=4(x+1)+x(x-2)/(x+1)(x-2)=x^2/(x+1)(x-2)`

   `=4x+4+x^2-2x=x^2`

   `=x=-2`

    

   Trả lời