1, (1+2x)(2x-1) 2, (4y^2+4xy+4x^2)(2x-2y) 03/10/2021 Bởi Eliza 1, (1+2x)(2x-1) 2, (4y^2+4xy+4x^2)(2x-2y)
`1, (1+2x)(2x-1)``= (2x+1).(2x-1)``= (2x)^2 -1^2``= 4x^2 -1` `2, (4y^2+4xy+4x^2)(2x-2y)`` = 4.(y^2 + 2xy+x^2).2.(x-y)``= 2^2.(x+y)^2 . 2.(x-y)``=2.(2x+2y)^2.(x-y)` Bình luận
Đáp án: `1,(2x+1)(2x-1)=(2x)^2-1^2=4x^2-1` `2,(4x^2+4xy+4y^2)(2x-2y)` `=[4(x^2+xy+y^2)].[2(x-y)]` `=[4(x+y)^2].[2(x-y)]` `=[2.(x+y)]^2 .[2(x-y)]` `=2.(2x+2y)^2 . (x-y)` Bình luận
`1, (1+2x)(2x-1)`
`= (2x+1).(2x-1)`
`= (2x)^2 -1^2`
`= 4x^2 -1`
`2, (4y^2+4xy+4x^2)(2x-2y)`
` = 4.(y^2 + 2xy+x^2).2.(x-y)`
`= 2^2.(x+y)^2 . 2.(x-y)`
`=2.(2x+2y)^2.(x-y)`
Đáp án:
`1,(2x+1)(2x-1)=(2x)^2-1^2=4x^2-1`
`2,(4x^2+4xy+4y^2)(2x-2y)`
`=[4(x^2+xy+y^2)].[2(x-y)]`
`=[4(x+y)^2].[2(x-y)]`
`=[2.(x+y)]^2 .[2(x-y)]`
`=2.(2x+2y)^2 . (x-y)`