-1`1/2`-x=`-2/3`+0,75 I`4/5`-xI-`1/10`=`2/5`

0 bình luận về “-1`1/2`-x=`-2/3`+0,75 I`4/5`-xI-`1/10`=`2/5`”

1. Giải thích các bước giải:

   `1\frac{1}{2}-x=-\frac{2}{3}+0,75`

   `\frac{3}{2} -x=-\frac{2}{3}+\frac{3}{4}`

   `\frac{3}{2} -x=\frac{1}{12}`

                   `x=\frac{3}{2}-\frac{1}{12}`

                   `x=\frac{17}{12}`

   `——————-`

   `|\frac{4}{5}-x|-\frac{1}{10}=\frac{2}{5}`

   `|\frac{4}{5}-x|=\frac{2}{5}+\frac{1}{10}`

   `|\frac{4}{5}-x|=\frac{5}{10}`

   `\frac{4}{5}-x=\frac{5}{10}` hoặc `\frac{4}{5}-x=-\frac{5}{10}`

   `x=\frac{4}{5}-\frac{5}{10}`          `x=\frac{4}{5}-(-\frac{5}{10})`

   `x=\frac{3}{10}`                            `x=\frac{13}{10}`

               `#Xuka`

   Bình luận

2.      `-1 1/2 -x = -2/3 +0,75`

   `=> (-1)/2 – x = -2/3 + 3/4`

   `=> (-1)/2 – x = -8/12 + 9/12`

   `=> (-1)/2 – x = 1/12`

   `=> x = (-1)/2 – 1/12`

   `=> x = (-6)/12 – 1/12`

   `=> x = (-7)/12`

   ` – – – –  –`

         `| 4/5 -x| -1/10 = 2/5`

   `=> |4/5 – x| = 2/5 + 1/10`

   `=> |4/5 – x| = 4/10 + 1/10`

   `=> | 4/5 -x| = 1/2`

   $ ⇒\left[ \begin{array}{l}\dfrac{4}{5} – x = \dfrac{1}{2}\\\dfrac{4}{5} – x = \dfrac{-1}2\end{array} \right.\\⇒\left[ \begin{array}{l}x=\dfrac{3}{10}\\x=\dfrac{13}{10}\\\end{array} \right.$

    

   Bình luận