Toán -1`1/2`-x=`-2/3`+0,75 I`4/5`-xI-`1/10`=`2/5` 17/07/2021 By Madeline -1`1/2`-x=`-2/3`+0,75 I`4/5`-xI-`1/10`=`2/5`
`-1 1/2 – x = ( – 2 )/3 + 0,75` `⇔ ( – 3 )/2 – x = ( – 2 )/3 + 3/4` `⇔ ( – 3 )/2 – x = 1/12` `⇔ x = ( – 3 )/2 – 1/12` `⇔ x = ( – 19 )/12` Vậy , `x = ( – 19 )/12` _____________________________________ `| 4/5 – x | – 1/10 = 2/5` `⇔ | 4/5 – x | = 2/5 + 1/10` `⇔ | 4/5 – x | = 1/2` Trường hợp `1 : 4/5 – x = 1/2` `⇔ x = 4/5 – 1/2` `⇔ x = 3/10` Trường hợp `2 : 4/5 – x = ( – 1 )/2` `⇔ x = 4/5 – ( – 1 )/2` `⇔ x = 13/10` Vậy , `x ∈ { 3/10 ; 13/10 }` Trả lời
Giải thích các bước giải: `-1 1/2-x=-2/3+0,75``=>-3/2 -x=-2/3+3/4``=>-3/2-x=-8/12+9/12``=>-3/2-x=1/12``=>x=-3/2-1/12``=>x=-18/12-1/12``=>x=-19/12`Vậy `x=-19/12``|4/5-x|-1/10=2/5``=>|4/5-x|=2/5+1/10``=>|4/5-x|=4/10+1/10``=>|4/5-x|=5/10``=>|4/5-x|=1/2`TH`1`:`4/5-x=1/2``=>x=4/5-1/2``=>x=3/10`TH`2``4/5-x=-1/2``=>x=4/5+1/2``=>x=13/10`Vậy `\in{3/10;13/10}` Trả lời
`-1 1/2 – x = ( – 2 )/3 + 0,75`
`⇔ ( – 3 )/2 – x = ( – 2 )/3 + 3/4`
`⇔ ( – 3 )/2 – x = 1/12`
`⇔ x = ( – 3 )/2 – 1/12`
`⇔ x = ( – 19 )/12`
Vậy , `x = ( – 19 )/12`
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`| 4/5 – x | – 1/10 = 2/5`
`⇔ | 4/5 – x | = 2/5 + 1/10`
`⇔ | 4/5 – x | = 1/2`
Trường hợp `1 : 4/5 – x = 1/2`
`⇔ x = 4/5 – 1/2`
`⇔ x = 3/10`
Trường hợp `2 : 4/5 – x = ( – 1 )/2`
`⇔ x = 4/5 – ( – 1 )/2`
`⇔ x = 13/10`
Vậy , `x ∈ { 3/10 ; 13/10 }`
Giải thích các bước giải:
`-1 1/2-x=-2/3+0,75`
`=>-3/2 -x=-2/3+3/4`
`=>-3/2-x=-8/12+9/12`
`=>-3/2-x=1/12`
`=>x=-3/2-1/12`
`=>x=-18/12-1/12`
`=>x=-19/12`
Vậy `x=-19/12`
`|4/5-x|-1/10=2/5`
`=>|4/5-x|=2/5+1/10`
`=>|4/5-x|=4/10+1/10`
`=>|4/5-x|=5/10`
`=>|4/5-x|=1/2`
TH`1`:
`4/5-x=1/2`
`=>x=4/5-1/2`
`=>x=3/10`
TH`2`
`4/5-x=-1/2`
`=>x=4/5+1/2`
`=>x=13/10`
Vậy `\in{3/10;13/10}`