1,x:1,75=1 3/10+45% 2,5-x/12+5/12-1/8=3/8 3,|x-25/35|-3/11=2/3 29/11/2021 Bởi Maya 1,x:1,75=1 3/10+45% 2,5-x/12+5/12-1/8=3/8 3,|x-25/35|-3/11=2/3
Đáp án: $\begin{array}{l}1)x:1,75 = 1\frac{3}{{10}} + 45\% \\ \Rightarrow x:\frac{{175}}{{100}} = \frac{{13}}{{10}} + \frac{{45}}{{100}}\\ \Rightarrow x:\frac{{175}}{{100}} = \frac{{13}}{{10}} + \frac{9}{{20}}\\ \Rightarrow x:\frac{7}{4} = \frac{{26 + 9}}{{20}} = \frac{{35}}{{20}}\\ \Rightarrow x = \frac{{35}}{{20}}.\frac{7}{4} = \frac{{49}}{{16}}\\2)\frac{{5 – x}}{{12}} + \frac{5}{{12}} – \frac{1}{8} = \frac{3}{8}\\ \Rightarrow \frac{{5 – x + 5}}{{12}} = \frac{3}{8} + \frac{1}{8} = \frac{1}{2}\\ \Rightarrow \frac{{10 – x}}{{12}} = \frac{1}{2} = \frac{6}{{12}}\\ \Rightarrow 10 – x = 6\\ \Rightarrow x = 10 – 6 = 4\\Vay\,x = 4\\3)\left| {x – \frac{{25}}{{35}}} \right| – \frac{3}{{11}} = \frac{2}{3}\\ \Rightarrow \left| {x – \frac{5}{7}} \right| = \frac{2}{3} + \frac{3}{{11}} = \frac{{22 + 9}}{{33}} = \frac{{31}}{{33}}\\ \Rightarrow \left[ \begin{array}{l}x – \frac{5}{7} = \frac{{31}}{{33}}\\x – \frac{5}{7} = – \frac{{31}}{{33}}\end{array} \right.\\ \Rightarrow \left[ \begin{array}{l}x = \frac{{31}}{{33}} + \frac{5}{7} = \frac{{31.7 + 5.33}}{{33.7}} = \frac{{382}}{{231}}\\x = \frac{{ – 31}}{{33}} + \frac{5}{7} = \frac{{ – 52}}{{231}}\end{array} \right.\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
1)x:1,75 = 1\frac{3}{{10}} + 45\% \\
\Rightarrow x:\frac{{175}}{{100}} = \frac{{13}}{{10}} + \frac{{45}}{{100}}\\
\Rightarrow x:\frac{{175}}{{100}} = \frac{{13}}{{10}} + \frac{9}{{20}}\\
\Rightarrow x:\frac{7}{4} = \frac{{26 + 9}}{{20}} = \frac{{35}}{{20}}\\
\Rightarrow x = \frac{{35}}{{20}}.\frac{7}{4} = \frac{{49}}{{16}}\\
2)\frac{{5 – x}}{{12}} + \frac{5}{{12}} – \frac{1}{8} = \frac{3}{8}\\
\Rightarrow \frac{{5 – x + 5}}{{12}} = \frac{3}{8} + \frac{1}{8} = \frac{1}{2}\\
\Rightarrow \frac{{10 – x}}{{12}} = \frac{1}{2} = \frac{6}{{12}}\\
\Rightarrow 10 – x = 6\\
\Rightarrow x = 10 – 6 = 4\\
Vay\,x = 4\\
3)\left| {x – \frac{{25}}{{35}}} \right| – \frac{3}{{11}} = \frac{2}{3}\\
\Rightarrow \left| {x – \frac{5}{7}} \right| = \frac{2}{3} + \frac{3}{{11}} = \frac{{22 + 9}}{{33}} = \frac{{31}}{{33}}\\
\Rightarrow \left[ \begin{array}{l}
x – \frac{5}{7} = \frac{{31}}{{33}}\\
x – \frac{5}{7} = – \frac{{31}}{{33}}
\end{array} \right.\\
\Rightarrow \left[ \begin{array}{l}
x = \frac{{31}}{{33}} + \frac{5}{7} = \frac{{31.7 + 5.33}}{{33.7}} = \frac{{382}}{{231}}\\
x = \frac{{ – 31}}{{33}} + \frac{5}{7} = \frac{{ – 52}}{{231}}
\end{array} \right.
\end{array}$