1,x ²+x-12 2,4+3x ²-8x 3,x ²-2x-8 4,7x-3x ²-2

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1. 1) `x^2+x-12`

   `=x^2 -3x+4x-12`

   `=x(x-3)+4(x-3)`

   `=(x-3)(x+4)`

   2) `4+3x^2-8x`

   `=3x^2 – 2x-6x+4`

   `=x(3x-2)-2(3x-2)`

   `=(3x-2)(x-2)`

   3) `x^2-2x-8`

   `=x^2+2x-4x-8`

   `=x(x+2)-4(x+2)`

   `=(x+2)(x-4)`

   4) `7x-3x^2-2`

   `= -3x^2 +6x+x-2`

   `=-3x(x-2)+(x-2)`

   `=(x-1)(-3x+1)`

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2. Đáp án:

   ↓↓↓

   Giải thích các bước giải:

    1. `x²+x-12`

   = `x²+4x-3x-12`

   = `x(x+4)-3(x+4)`

   = `(x-3)(x+4`

   2. `4+3x²-8x`

   = `4+3x²-2x-6x`

   = `x(3x-2)-2(3x-2)`

   = `(x-2)(3x-20)`

   3. `x²-2x-8`

   = `x²+2x-4x-8`

   = `x(x+2)-4(x+2)`

   = `(x-4)(x+2)`

   4. `7x-3x²-2`

   = `x+6x-3x²-2`

   = `3x(x-2)+(x-2)`

   = `(3x+1)(x-2)`

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