(x – 1)(x + 12) lớn hơn 0 nhanh lên nha 01/10/2021 Bởi Hadley (x – 1)(x + 12) lớn hơn 0 nhanh lên nha
Đáp án: `(x – 1)(x + 12) > 0` `*` Th1 ; `x-1 > 0 -> x > 1 ` `x+12 > 0 -> x > -12` `*` Th2 : `x-1 < 0 -> x <1` `x+12 < 0 -> x <-12 ` `=> x >1` hoặc `x<-12` `Go od luck!` Bình luận
`(x – 1)(x + 12) > 0` `⇒` \(\left[ \begin{array}{l}x – 1 >0 ;x + 12 > 0\\x-1<0;x+ 12<0\end{array} \right.\) `⇒` \(\left[ \begin{array}{l}x >1 ;x > -12\\x<1;x<-12\end{array} \right.\) `⇒` \(\left[ \begin{array}{l}x > 1\\x<-12\end{array} \right.\) Bình luận
Đáp án:
`(x – 1)(x + 12) > 0`
`*` Th1 ;
`x-1 > 0 -> x > 1 `
`x+12 > 0 -> x > -12`
`*` Th2 :
`x-1 < 0 -> x <1`
`x+12 < 0 -> x <-12 `
`=> x >1` hoặc `x<-12`
`Go od luck!`
`(x – 1)(x + 12) > 0`
`⇒` \(\left[ \begin{array}{l}x – 1 >0 ;x + 12 > 0\\x-1<0;x+ 12<0\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x >1 ;x > -12\\x<1;x<-12\end{array} \right.\)
`⇒` \(\left[ \begin{array}{l}x > 1\\x<-12\end{array} \right.\)