( x + 1) ^2 = 0 x ( x – 5) = 0 ( 2x + 4) . ( 3x + 3) = 0 02/11/2021 Bởi Cora ( x + 1) ^2 = 0 x ( x – 5) = 0 ( 2x + 4) . ( 3x + 3) = 0
Bài làm : `(x+1)^2 = 0` `⇔(x+1)(x+1)=0` `⇔x(x+1)+1(x+1)=0` `⇔x^2 +1x+1(x+1)=0` `⇔x^2 +1+x+1=0` `⇔x=-1` Vậy `x=-1` — `x(x-5)=0` ⇔ \(\left[ \begin{array}{l}x=0\\x-5=0\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=0\\x=5\end{array} \right.\) Vậy `x∈{0;5}` — `( 2x + 4) . ( 3x + 3) = 0` ⇔ \(\left[ \begin{array}{l}2x +4 = 0\\3x + 3 = 0\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}2x=-4\\3x=-3\end{array} \right.\) ⇔ \(\left[ \begin{array}{l}x=-2\\x=-1\end{array} \right.\) Vậy `x ∈ { -2 ; -1 }` Bình luận
a) ( x +1 )^2=0 ( x+1 )^2=0^2 x+1=0 x=0-1 x=-1 b) x.(x-5)=0 x.(x-5)=5.0 => x=5 c) (2x+4).(3x+3)=0 => 2x+4 =0 hoặc 3x+3=0 +T/h 1 : 2x+4=0 2x=0-4 2x=-4 x=-4:2 x=-2 +T/h 2 : 3x+3=0 3x=0-3 3x=-3 x=-3:3 x=-1 Cho mk 5* và câu trả lời hay nhất nha ! Bình luận
Bài làm :
`(x+1)^2 = 0`
`⇔(x+1)(x+1)=0`
`⇔x(x+1)+1(x+1)=0`
`⇔x^2 +1x+1(x+1)=0`
`⇔x^2 +1+x+1=0`
`⇔x=-1`
Vậy `x=-1`
—
`x(x-5)=0`
⇔ \(\left[ \begin{array}{l}x=0\\x-5=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=0\\x=5\end{array} \right.\)
Vậy `x∈{0;5}`
—
`( 2x + 4) . ( 3x + 3) = 0`
⇔ \(\left[ \begin{array}{l}2x +4 = 0\\3x + 3 = 0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}2x=-4\\3x=-3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=-2\\x=-1\end{array} \right.\)
Vậy `x ∈ { -2 ; -1 }`
a) ( x +1 )^2=0
( x+1 )^2=0^2
x+1=0
x=0-1
x=-1
b) x.(x-5)=0
x.(x-5)=5.0
=> x=5
c) (2x+4).(3x+3)=0
=> 2x+4 =0 hoặc 3x+3=0
+T/h 1 :
2x+4=0
2x=0-4
2x=-4
x=-4:2
x=-2
+T/h 2 :
3x+3=0
3x=0-3
3x=-3
x=-3:3
x=-1
Cho mk 5* và câu trả lời hay nhất nha !