Đáp án: \(\text{$x=\dfrac{5}{2}$ hoặc $x=\dfrac{-3}{2}$}\) Giải thích các bước giải: \(\left |x-\dfrac{1}{2} \right |+\dfrac{1}{2}=2\dfrac{1}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |+\dfrac{1}{2}=\dfrac{5}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |=\dfrac{5}{2}-\dfrac{1}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |=2\\ ⇔\left[ \begin{array}{l}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{array} \right.\\ ⇔\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=\dfrac{-3}{2}\end{array} \right.\\ \text{Vậy $x=\dfrac{5}{2}$ hoặc $x=\dfrac{-3}{2}$}\) chúc em học tốt! Bình luận
`|x-1/2|+1/2=2 1/2` `⇒ |x-1/2|+1/2=5/2` `⇒ |x-1/2|=5/2-1/2` `⇒ |x-1/2|=2` `⇒ x-1/2=2` `⇒ x-1/2=-2` ` x=2+1/2=5/2` `⇒ x=-2+1/2=-3/2` Bình luận
Đáp án:
\(\text{$x=\dfrac{5}{2}$ hoặc $x=\dfrac{-3}{2}$}\)
Giải thích các bước giải:
\(\left |x-\dfrac{1}{2} \right |+\dfrac{1}{2}=2\dfrac{1}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |+\dfrac{1}{2}=\dfrac{5}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |=\dfrac{5}{2}-\dfrac{1}{2}\\ ⇔\left |x-\dfrac{1}{2} \right |=2\\ ⇔\left[ \begin{array}{l}x-\dfrac{1}{2}=2\\x-\dfrac{1}{2}=-2\end{array} \right.\\ ⇔\left[ \begin{array}{l}x=\dfrac{5}{2}\\x=\dfrac{-3}{2}\end{array} \right.\\ \text{Vậy $x=\dfrac{5}{2}$ hoặc $x=\dfrac{-3}{2}$}\)
chúc em học tốt!
`|x-1/2|+1/2=2 1/2`
`⇒ |x-1/2|+1/2=5/2`
`⇒ |x-1/2|=5/2-1/2`
`⇒ |x-1/2|=2`
`⇒ x-1/2=2` `⇒ x-1/2=-2`
` x=2+1/2=5/2` `⇒ x=-2+1/2=-3/2`