1) (x^2-2x-1).(x-3) 2) (2x-1).(x^2-5x+3) ae lào jỏi toán jup mị vs 30/07/2021 Bởi Lydia 1) (x^2-2x-1).(x-3) 2) (2x-1).(x^2-5x+3) ae lào jỏi toán jup mị vs
` 1) ` ` (x^2 – 2x – 1)(x – 3) ` ` = x^2 (x – 3) – 2x(x – 3) – (x – 3) ` ` = x^3 – 3x^2 – 2x^2 + 6x – x + 3 ` ` = x^3 – 5x^2 + 5x + 3 ` ` 2) ` ` (2x – 1)(x^2 – 5x + 3) ` ` = 2x(x^2 – 5x + 3) – (x^2 – 5x + 3) ` ` = 2x^3 – 10x^2 + 6x – x^2 + 5x – 3 ` ` = 2x^3 – 10x^2 – x^2 + 6x + 5x – 3 ` ` = 2x^3 – 11x^2 + 11x – 3 ` Bình luận
@Queen `1) (x^2-2x-1).(x-3)` `= x^3 – 2x^2 – x – 3x^2 + 6x + 3` `= x^3 – 5x^2 + 5x + 3` `2)(2x-1).(x^2-5x+3)` `= 2x^3 – 10x^2 + 6x – x^2 + 5x – 3` `= 2x^3 – 11x^2 + 11x -3` Bình luận
` 1) `
` (x^2 – 2x – 1)(x – 3) `
` = x^2 (x – 3) – 2x(x – 3) – (x – 3) `
` = x^3 – 3x^2 – 2x^2 + 6x – x + 3 `
` = x^3 – 5x^2 + 5x + 3 `
` 2) `
` (2x – 1)(x^2 – 5x + 3) `
` = 2x(x^2 – 5x + 3) – (x^2 – 5x + 3) `
` = 2x^3 – 10x^2 + 6x – x^2 + 5x – 3 `
` = 2x^3 – 10x^2 – x^2 + 6x + 5x – 3 `
` = 2x^3 – 11x^2 + 11x – 3 `
@Queen
`1) (x^2-2x-1).(x-3)`
`= x^3 – 2x^2 – x – 3x^2 + 6x + 3`
`= x^3 – 5x^2 + 5x + 3`
`2)(2x-1).(x^2-5x+3)`
`= 2x^3 – 10x^2 + 6x – x^2 + 5x – 3`
`= 2x^3 – 11x^2 + 11x -3`