1) (x^2-2x-1).(x-3) 2) (2x-1).(x^2-5x+3) ae lào jỏi toán jup mị vs

1) (x^2-2x-1).(x-3)
2) (2x-1).(x^2-5x+3)
ae lào jỏi toán jup mị vs

0 bình luận về “1) (x^2-2x-1).(x-3) 2) (2x-1).(x^2-5x+3) ae lào jỏi toán jup mị vs”

  1. ` 1) `

    ` (x^2 – 2x – 1)(x – 3) `

    ` = x^2 (x – 3) – 2x(x – 3) – (x – 3) `

    ` = x^3 – 3x^2 – 2x^2 + 6x – x + 3 `

    ` = x^3 – 5x^2 + 5x + 3 `

    ` 2) `

    ` (2x – 1)(x^2 – 5x + 3) `

    ` = 2x(x^2 – 5x + 3) – (x^2 – 5x + 3) `

    ` = 2x^3 – 10x^2 + 6x – x^2 + 5x – 3 `

    ` = 2x^3 – 10x^2 – x^2 + 6x + 5x – 3 `

    ` = 2x^3 – 11x^2 + 11x – 3 `

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  2. @Queen

    `1) (x^2-2x-1).(x-3)`

    `= x^3 – 2x^2 – x – 3x^2 + 6x + 3`

    `= x^3 – 5x^2 + 5x + 3`

    `2)(2x-1).(x^2-5x+3)`

    `= 2x^3 – 10x^2 + 6x – x^2 + 5x – 3`

    `= 2x^3 – 11x^2 + 11x -3`

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