(x+1/2)^2=4/25 moi nghuoi lam ho em voi a 16/07/2021 Bởi Lydia (x+1/2)^2=4/25 moi nghuoi lam ho em voi a
$( x+ \frac{1}{2} )^2 = \frac{4}{25}$ <=> $ \sqrt{ (x + \frac{1}{2} )^2 } = \sqrt{ \frac{4}{25} }$ <=> $ | x+ \frac{1}{2}| = \frac{2}{5}$ * TH1: $ x+ \frac{1}{2} = \frac{2}{5}$ <=> $ x= \frac{-1}{10}$ * TH2: $ x+ \frac{1}{2} = \frac{-2}{5}$ <=> $ x= \frac{-9}{10}$ Vậy $ S= ( \frac{-1}{10}; \frac{-9}{10} )$ Bình luận
Đáp án đây ạ
$( x+ \frac{1}{2} )^2 = \frac{4}{25}$
<=> $ \sqrt{ (x + \frac{1}{2} )^2 } = \sqrt{ \frac{4}{25} }$
<=> $ | x+ \frac{1}{2}| = \frac{2}{5}$
* TH1: $ x+ \frac{1}{2} = \frac{2}{5}$
<=> $ x= \frac{-1}{10}$
* TH2: $ x+ \frac{1}{2} = \frac{-2}{5}$
<=> $ x= \frac{-9}{10}$
Vậy $ S= ( \frac{-1}{10}; \frac{-9}{10} )$