Toán 1/2 x2 ( 6x – 3 ) – x ( x2 + 1/2 ) ( x + 4 ) 12/07/2021 By Delilah 1/2 x2 ( 6x – 3 ) – x ( x2 + 1/2 ) ( x + 4 )
`#DyHungg` `1/2x²(6x-3)-x(x²+1/2)(x+4)` `=3x³-3/2x²-(x³+1/2x)(x+4)` `=3x³-3/2x²-(x^4+4x³+1/2x²+2x)` `=3x³-3/2x²-x^4-4x³-1/2x²-2x` `=-x³-2x²-x^4-2x` Trả lời
Đáp án: `1/2 x^2 (6x – 3) – x (x^2 + 1/2) (x + 4)` `= 3x^3 – 3/2x^2 – (x^3 + 1/2x) (x + 4)` `= 3x^3 – 3/2x^2 -[ x^3 (x + 4) + 1/2x (x + 4)]` `= 3x^3 – 3/2x^2 – [x^4 + 4x^3 + 1/2x^2 + 2x]` `= 3x^3 – 3/2x^2 – x^4 – 4x^3 – 1/2x^2 – 2x` `= (3x^3 – 4x^3) + (-3/2x^2 – 1/2x^2) – x^4 – 2x` `= -x^3 – 2x^2 – x^4 – 2x` Trả lời
`#DyHungg`
`1/2x²(6x-3)-x(x²+1/2)(x+4)`
`=3x³-3/2x²-(x³+1/2x)(x+4)`
`=3x³-3/2x²-(x^4+4x³+1/2x²+2x)`
`=3x³-3/2x²-x^4-4x³-1/2x²-2x`
`=-x³-2x²-x^4-2x`
Đáp án:
`1/2 x^2 (6x – 3) – x (x^2 + 1/2) (x + 4)`
`= 3x^3 – 3/2x^2 – (x^3 + 1/2x) (x + 4)`
`= 3x^3 – 3/2x^2 -[ x^3 (x + 4) + 1/2x (x + 4)]`
`= 3x^3 – 3/2x^2 – [x^4 + 4x^3 + 1/2x^2 + 2x]`
`= 3x^3 – 3/2x^2 – x^4 – 4x^3 – 1/2x^2 – 2x`
`= (3x^3 – 4x^3) + (-3/2x^2 – 1/2x^2) – x^4 – 2x`
`= -x^3 – 2x^2 – x^4 – 2x`