-1,2 .x +3/2 =5,6 2^3+2 ( hai mũ ba cộng hai ) = 4 x+5 ( bốn mũ x cộng 5) 04/07/2021 Bởi Sarah -1,2 .x +3/2 =5,6 2^3+2 ( hai mũ ba cộng hai ) = 4 x+5 ( bốn mũ x cộng 5)
-1,2 . x + 3/2 = 5/6 -6/5x = 5/6 – 3/2 -6/5x = -2/3 x = -2/3 : -6/5 x = 5/9 Vậy x = 5/9 2³ + 2 = 4^x + 5 ⇒ 4^x + 5 = 2³ + 2 ⇒ 4^x + 5 = 8 + 2 ⇒ 4^x + 5 = 10 ⇒4^x = 10 – 5 ⇒ 4^x = 5 ⇒ x ∈ ∅ Vậy x ∈ ∅ Bình luận
$-1,2x+\dfrac{3}{2}=5,6$ $↔-1,2x=5,6-\dfrac{3}{2}$ $↔-1,2x=\dfrac{41}{10}$ $↔x=\dfrac{41}{10}:(-1,2)$ $→x=-\dfrac{41}{12}$ b) $2^{3+2}=4^{x+5}$ $↔2^5=2^{2(x+5)}$ $↔2^5=2^{2x+10}$ $↔5=2x+10$ $↔-5=2x$ $→-\dfrac{5}{2}=x$ Bình luận
-1,2 . x + 3/2 = 5/6
-6/5x = 5/6 – 3/2
-6/5x = -2/3
x = -2/3 : -6/5
x = 5/9
Vậy x = 5/9
2³ + 2 = 4^x + 5
⇒ 4^x + 5 = 2³ + 2
⇒ 4^x + 5 = 8 + 2
⇒ 4^x + 5 = 10
⇒4^x = 10 – 5
⇒ 4^x = 5
⇒ x ∈ ∅
Vậy x ∈ ∅
$-1,2x+\dfrac{3}{2}=5,6$
$↔-1,2x=5,6-\dfrac{3}{2}$
$↔-1,2x=\dfrac{41}{10}$
$↔x=\dfrac{41}{10}:(-1,2)$
$→x=-\dfrac{41}{12}$
b) $2^{3+2}=4^{x+5}$
$↔2^5=2^{2(x+5)}$
$↔2^5=2^{2x+10}$
$↔5=2x+10$
$↔-5=2x$
$→-\dfrac{5}{2}=x$