Toán (x+1)^2=4(x^2-2x+1) giúp mik mik vote5 sao 08/09/2021 By Rylee (x+1)^2=4(x^2-2x+1) giúp mik mik vote5 sao
`(x+1)^2=4(x^2-2x+1)` `<=>(x+1)^2=4x^2-8x+4` `<=>(x+1)^2-(2x-2)^2=0` `<=>(x+1+2x-2)(x-1-2x+2)=0` `<=>(3x-1)(-x+3)=0` `TH1:3x-1=0=>x =1/3` `TH2:-x+3=0=>x=3` Vậy pt có no `x=1/3 và 3` Trả lời
Đáp án: `S={1;1/3}` Giải thích các bước giải: `(x+1)^2=4(x^2-2x+1)` `<=>(x+1)^2=4(x-1)^2` `<=>(x+1)^2=[2(x-1)]^2` `<=>(x+1)^2=(2x-2)^2` `<=>(x+1)^2-(2x-2)^2=0` `<=>(x+1-2x+2)(x+1+2x-2)=0` `<=>(3-x)(3x-1)=0` `<=>` \(\left[ \begin{array}{l}3-x=0\\3x-1=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{3}\end{array} \right.\) Vậy `S={3;1/3}` Trả lời
`(x+1)^2=4(x^2-2x+1)`
`<=>(x+1)^2=4x^2-8x+4`
`<=>(x+1)^2-(2x-2)^2=0`
`<=>(x+1+2x-2)(x-1-2x+2)=0`
`<=>(3x-1)(-x+3)=0`
`TH1:3x-1=0=>x =1/3`
`TH2:-x+3=0=>x=3`
Vậy pt có no `x=1/3 và 3`
Đáp án:
`S={1;1/3}`
Giải thích các bước giải:
`(x+1)^2=4(x^2-2x+1)`
`<=>(x+1)^2=4(x-1)^2`
`<=>(x+1)^2=[2(x-1)]^2`
`<=>(x+1)^2=(2x-2)^2`
`<=>(x+1)^2-(2x-2)^2=0`
`<=>(x+1-2x+2)(x+1+2x-2)=0`
`<=>(3-x)(3x-1)=0`
`<=>` \(\left[ \begin{array}{l}3-x=0\\3x-1=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=3\\x=\dfrac{1}{3}\end{array} \right.\)
Vậy `S={3;1/3}`