x/x-1+2x+6/x^2-3x-2/x^2-x): x^2-x+4/x^2-4x+3 rút gọn 05/12/2021 Bởi Alice x/x-1+2x+6/x^2-3x-2/x^2-x): x^2-x+4/x^2-4x+3 rút gọn
`\text{~~Holi~~}` `(x/(x-1)+(2x+6)/(x^2-3x)-2/(x^2-x)) : (x^2-x+4)/(x^2-4x+3)` `-> (x/(x-1)+(2x+6)/(x^2-3x)-2/(x^2-x)) . (x^2-4x+3)/(x^2-x+4)` `-> ((x^3-3x^2+2x^2+6x-2x-6-2x+6)/(x(x-3)(x-1))) . ((x-1)(x-3))/(x^2-x+4)` `-> (x^3-x^2+2x)/((x(x-3)(x-1))“.“((x-1)(x-3))/(x^2-x+4)` `-> (x(x^2-x+2))/(x(x-3)) . ((x-1)(x-3))/(x^2-x+4)` `-> (x^2-x+2)/(x-3) . (x-3)/(x^2-x+4)` `-> (x^2-x+2).(1/(x^2-x+4))` `-> (x^2-x+2)/(x^2-x+4)` Bình luận
Đáp án:= 2+x2−x- 4×24−x2- 2−x2+x : x2−3x2x2−x3 = (2+x)(2+x)−4×2+(2−x)(2−x)4−x2 . 2×2−x3x2−3x = 4+4x+x2−4×2−4+4x−x24−x2. 2×2−x3x2−3x = 8x−4×24−x2. 2×2−x3x2−3x = 8−4×22+x. x2x−3 Giải thích các bước giải:xong Bình luận
`\text{~~Holi~~}`
`(x/(x-1)+(2x+6)/(x^2-3x)-2/(x^2-x)) : (x^2-x+4)/(x^2-4x+3)`
`-> (x/(x-1)+(2x+6)/(x^2-3x)-2/(x^2-x)) . (x^2-4x+3)/(x^2-x+4)`
`-> ((x^3-3x^2+2x^2+6x-2x-6-2x+6)/(x(x-3)(x-1))) . ((x-1)(x-3))/(x^2-x+4)`
`-> (x^3-x^2+2x)/((x(x-3)(x-1))“.“((x-1)(x-3))/(x^2-x+4)`
`-> (x(x^2-x+2))/(x(x-3)) . ((x-1)(x-3))/(x^2-x+4)`
`-> (x^2-x+2)/(x-3) . (x-3)/(x^2-x+4)`
`-> (x^2-x+2).(1/(x^2-x+4))`
`-> (x^2-x+2)/(x^2-x+4)`
Đáp án:= 2+x2−x- 4×24−x2- 2−x2+x : x2−3x2x2−x3
= (2+x)(2+x)−4×2+(2−x)(2−x)4−x2 . 2×2−x3x2−3x
= 4+4x+x2−4×2−4+4x−x24−x2. 2×2−x3x2−3x
= 8x−4×24−x2. 2×2−x3x2−3x
= 8−4×22+x. x2x−3
Giải thích các bước giải:xong