X+1/2020 + X+2/2019 = X-1/2023 + X-2/2022

0 bình luận về “X+1/2020 + X+2/2019 = X-1/2023 + X-2/2022”

1. `(x + 1)/2020 + (x + 2)/2019 = (x – 1)/2023 + (x – 2)/2022`

   `⇒ (x + 1)/2020 + 1 + (x + 2)/2019 + 1= (x – 1)/2023 + 1 + (x – 2)/2022 + 1`

   `⇒ (x + 2021)/2020 + (x + 2021)/2019 = (x + 2021)/2023 + (x + 2021)/2022`

   `⇒ (x + 2021)/2020 + (x + 2021)/2019 – (x + 2021)/2023 – (x + 2021)/2022 = 0`

    `⇒ (x + 2021)(1/2020 + 1/2019 – 1/2023 – 1/2022) = 0`

   Ta thấy `(1/2020 + 1/2019 – 1/2023 – 1/2022) \ne 0`

   `⇒ x + 2021 = 0 ⇒ x = -2021` 

   Bình luận