1,-25x^6-y^8+10x^3y^4
2,(x+y)^2-25
3,27+27x+9x^2+x^3
4,1-4x^2
5,x^6-x^4+2x^3+2x
6,4x^2+12x+9
7,x^4+64
8,x^2-xy-8x+8y
9,2x^2+2y^2-x^2z+z-y^2z-2
10,8-27x^3
1,-25x^6-y^8+10x^3y^4
2,(x+y)^2-25
3,27+27x+9x^2+x^3
4,1-4x^2
5,x^6-x^4+2x^3+2x
6,4x^2+12x+9
7,x^4+64
8,x^2-xy-8x+8y
9,2x^2+2y^2-x^2z+z-y^2z-2
10,8-27x^3
Đáp án:
Giải thích các bước giải:
$1)-25x^6 – y^8 + 10x^3y^4$
$=-(25x^6 – 10x^3y^4 + y^8)$
$=-(5x^3 – y^4)$
$2)(x + y)^2 – 25$
$=(x + y – 5)(x + y + 5)$
$3)27 + 27x + 9x^2 + x^3$
$=(x+3)^3$
$4)1 – 4x^2$
$=-(4x^2 – 1)$
$=-(2x – 1)(2x + 1)$
$5)x^6 – x^4 + 2x^3 + 2x^2$
$=(x^3 + x^2)(x^3 – x^2) + 2x^2(x + 1)$
$=x^2(x + 1)(x^3 – x^2) + 2x^2(x + 1)$
$=(x + 1)(x^5 – x^6 + 2x^2)$
$=(x + 1)x^2(x^3 – x^4 + 2)$
$6)4x^2 + 12x + 9$
$=(2x + 3)^2$
$7)x^4 + 64$
$=(x^4 + 16x^2 + 64) – 16x^2$
$=(x^2 + 8) – 16x^2$
$=(x^2 + 8 + 4x)(x^2 + 8 – 4x)$
$8)x^2 – xy – 8x + 8y$
$=x(x – y) – 8(x – y)$
$=(x – 8)(x – y)$
$10)8 – 27x^3$
$=-(3x – 2)(9x^2 + 6x + 4)$
Đáp án:
Giải thích các bước giải:
1,-25x^6-y^8+10x^3y^4
=-(25x^6-10x³y^4+y^8)
=-(5x³-y^4)
2,(x+y)^2-25
=(x+y-5)(x+y+5)
3,27+27x+9x^2+x^3
=(x+3)³
4,1-4x^2
=-(4x²-1)
=-(2x-1)(2x+1)
5,x^6-x^4+2x^3+2x²
=(x³+x²)(x³-x²)+2x²(x+1)
=x²(x+1)(x³-x²)+2x²(x+1)
=(x+1)(x^5-x^6+2x²)
=(x+1)x²(x³-x^4+2)
6,4x^2+12x+9
=(2x+3)²
7,x^4+64
=(x^4+16x²+64)-16x²
=(x²+8)-16x²
=(x²+8+4x)(x²+8-4x)
8,x^2-xy-8x+8y
=x(x-y)-8(x-y)
=(x-8)(x-y)
10,8-27x^3
=-(3x-2)(9x²+6x+4)