1-|3/5x + 2/3| = 80% Các bạn giúp mình nha! :3 Hứa vote 5 sao+cảm ơn+ctlhn 06/11/2021 Bởi Camila 1-|3/5x + 2/3| = 80% Các bạn giúp mình nha! :3 Hứa vote 5 sao+cảm ơn+ctlhn
`1-|(3x)/5 + 2/3| = 80%` `⇔1-|(3x)/5 + 2/3| = 80/100=4/5` `⇔|(3x)/5 + 2/3| =4/5-1` `⇔|(3x)/5 + 2/3| =(-1)/5` ⇔\(\left[ \begin{array}{l}3x/5 + 2/3 =(-1)/5\\3x/5 + 2/3 =-(-1)/5\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=-13/9\\x=-7/9\end{array} \right.\) Bình luận
$1-\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=80\%\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=1-\dfrac{4}{5}\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=\dfrac{5-4}{5}\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=\dfrac{1}{5}\\⇔\left[\begin{array}{}\dfrac{3}{5}x+\dfrac{2}{3}=\dfrac{1}{5}\\\dfrac{3}{5}x+\dfrac{2}{3}=-\dfrac{1}{5}\end{array}\right.\\⇔\left[\begin{array}{}\dfrac{3}{5}x=\dfrac{1}{5}-\dfrac{2}{3}\\\dfrac{3}{5}x=-\dfrac{1}{5}-\dfrac{2}{3}\end{array}\right.\\⇔\left[\begin{array}{}\dfrac{3}{5}x=-\dfrac{7}{15}\\\dfrac{3}{5}x=-\dfrac{13}{15}\end{array}\right.\\⇔\left[\begin{array}{}x=-\dfrac{7}{15}.\dfrac{5}{3}\\x=-\dfrac{13}{15}.\dfrac{5}{3}\end{array}\right.\\⇔\left[\begin{array}{}x=-\dfrac{7}{9}\\x=-\dfrac{13}{9}\end{array}\right.$ Bình luận
`1-|(3x)/5 + 2/3| = 80%`
`⇔1-|(3x)/5 + 2/3| = 80/100=4/5`
`⇔|(3x)/5 + 2/3| =4/5-1`
`⇔|(3x)/5 + 2/3| =(-1)/5`
⇔\(\left[ \begin{array}{l}3x/5 + 2/3 =(-1)/5\\3x/5 + 2/3 =-(-1)/5\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-13/9\\x=-7/9\end{array} \right.\)
$1-\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=80\%\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=1-\dfrac{4}{5}\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=\dfrac{5-4}{5}\\⇔\Bigg|\dfrac{3}{5}x+\dfrac{2}{3}\Bigg|=\dfrac{1}{5}\\⇔\left[\begin{array}{}\dfrac{3}{5}x+\dfrac{2}{3}=\dfrac{1}{5}\\\dfrac{3}{5}x+\dfrac{2}{3}=-\dfrac{1}{5}\end{array}\right.\\⇔\left[\begin{array}{}\dfrac{3}{5}x=\dfrac{1}{5}-\dfrac{2}{3}\\\dfrac{3}{5}x=-\dfrac{1}{5}-\dfrac{2}{3}\end{array}\right.\\⇔\left[\begin{array}{}\dfrac{3}{5}x=-\dfrac{7}{15}\\\dfrac{3}{5}x=-\dfrac{13}{15}\end{array}\right.\\⇔\left[\begin{array}{}x=-\dfrac{7}{15}.\dfrac{5}{3}\\x=-\dfrac{13}{15}.\dfrac{5}{3}\end{array}\right.\\⇔\left[\begin{array}{}x=-\dfrac{7}{9}\\x=-\dfrac{13}{9}\end{array}\right.$