(x +1) + ( x+3) + (x + 5) + … + (x + 99) = 0 06/07/2021 Bởi Ximena (x +1) + ( x+3) + (x + 5) + … + (x + 99) = 0
(x +1) + ( x+3) + (x + 5) + … + (x + 99) = 0 ⇒50x+(1+3+…+99)=0 ⇒50x+2500=0 ⇒50x=-2500 ⇒x=-50 Bình luận
(x +1) + ( x+3) + (x + 5) + … + (x + 99) = 0
⇒50x+(1+3+…+99)=0
⇒50x+2500=0
⇒50x=-2500
⇒x=-50