1)4^|2x-1|=(-8)^2 2)0,55-2/3(x-1/1/8)=5/6 3)(x-2)^5=245 helpppppppppp 24/10/2021 Bởi Natalia 1)4^|2x-1|=(-8)^2 2)0,55-2/3(x-1/1/8)=5/6 3)(x-2)^5=245 helpppppppppp
1) $4^{|2x-1|}=(-8)^2$ $4^{|2x-1|}$ $=$ $4^3$ $|2x-1|=3$ ⇒ TH1: $2x-1=3$ ⇒ $x=2$ ⇒ TH2: $2x-1=-3$ ⇒ $x=-1$ 2) $0,55$ $-$ $\dfrac{2}{3}$.$(\dfrac{x-1}{1/8})$ $=$ $\dfrac{5}{6}$ $\dfrac{2}{3}$. $(\dfrac{x-1}{1/8})$ $=$ $0,55$ $-$ $\dfrac{5}{6}$ $=$ $\dfrac{-17}{60}$ $\dfrac{x-1}{1/8}$ $=$ $\dfrac{-17}{60}$ $.$ $\dfrac{3}{2}$ $=$ $\dfrac{-17}{40}$ $x-1$ $=$ $\dfrac{-17}{20}$ $.$ $\dfrac{1}{8}$ $=$ $\dfrac{-17}{320}$ 3) $(x-2)^5=245$ $x-2$=$\sqrt[5]{245}$ $x=$ $\sqrt[5]{245}-2$ ⇒ $x=$ $\dfrac{-17}{320}+1$ $=$ $\dfrac{303}{320}$ 3) Bình luận
Đáp án:
Giải thích các bước giải:
1) $4^{|2x-1|}=(-8)^2$
$4^{|2x-1|}$ $=$ $4^3$
$|2x-1|=3$
⇒ TH1: $2x-1=3$ ⇒ $x=2$
⇒ TH2: $2x-1=-3$ ⇒ $x=-1$
2) $0,55$ $-$ $\dfrac{2}{3}$.$(\dfrac{x-1}{1/8})$ $=$ $\dfrac{5}{6}$
$\dfrac{2}{3}$. $(\dfrac{x-1}{1/8})$ $=$ $0,55$ $-$ $\dfrac{5}{6}$ $=$ $\dfrac{-17}{60}$
$\dfrac{x-1}{1/8}$ $=$ $\dfrac{-17}{60}$ $.$ $\dfrac{3}{2}$ $=$ $\dfrac{-17}{40}$
$x-1$ $=$ $\dfrac{-17}{20}$ $.$ $\dfrac{1}{8}$ $=$ $\dfrac{-17}{320}$
3) $(x-2)^5=245$
$x-2$=$\sqrt[5]{245}$
$x=$ $\sqrt[5]{245}-2$
⇒ $x=$ $\dfrac{-17}{320}+1$ $=$ $\dfrac{303}{320}$
3)