1/ x-(-5)=1 2/ (-10)+x (x-1) 3/ 2+ (x – 2)=(-13) 4/ ( x+3) – 5= (-2) 5/ 8-( 1- x)=5 6/|x|=5 7/|x|-5=7 8/|x+2|=3 9/|x- 5|=10 10/|5- x|=2

0 bình luận về “1/ x-(-5)=1 2/ (-10)+x (x-1) 3/ 2+ (x – 2)=(-13) 4/ ( x+3) – 5= (-2) 5/ 8-( 1- x)=5 6/|x|=5 7/|x|-5=7 8/|x+2|=3 9/|x- 5|=10 10/|5- x|=2”

1. Đáp án:

   Tham khảo 

   Giải thích các bước giải:

    $1)x-(-5)=1$

   $x+5=1$

   $x=1-5=-4$

   $2)(-10)+x(x-1)$

   $=x^2-x-10$

   $3)2+(x-2)=-13$

   $x=-13+2-2$

   $x=-13$

   $4)(x+3)-5=-2$

   $x=-2+5-3$

   $x=0$

   $5)8-(1-x)=5$

   $x=5-8+1$

   $x=-2$

   $6)|x|=5$

   $x=±5$

   $7)|x|-5=7$

   $|x|=12$

   $x=±12$

   $8)|x+2|=3$

   $x+2=±3$

   $x=-5$ hay $x=1$

   $9)|x-5|=10$

   $x-5=±10$

   $x=15$ hay $x=-5$

   $10)|5-x|=2$

   $5-x=±2$

   $x=7$ hay $x=3$

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2. `1)x-(-5)=1`

   `→x+5=1`

   `→x=1-5`

   `→x=-4`

   Vậy `x=-4`

   `2)(-10)+x (x-1)`

   `=-10+x^2-x`

   `3)2+ (x – 2)=(-13)`

   `→2+x-2=-13`

   `→x=-13`

   Vậy `x=-13`

   `4)( x+3) – 5= (-2)`

   `→x+3=-2+5`

   `→x+3=3`

   `→x=0`

   Vậy `x=0`

   `5)8-( 1- x)=5`

   `→8-1+x=5`

   `→7+x=5`

   `→x=5-7`

   `→x=-2`

   `6)|x|=5`

   `→` \(\left[ \begin{array}{l}x=5\\x=-5\end{array} \right.\) 

   Vậy `x∈{5;-5}`

   `7)|x|-5=7`

   `→|x|=7+5`

   `→|x|=12`

   `→` \(\left[ \begin{array}{l}x=12\\x=-12\end{array} \right.\) 

   Vậy `x∈{12;-12}`

   `8)|x+2|=3`

   `→` \(\left[ \begin{array}{l}x+2=3\\x+2=-3\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=1\\x=-5\end{array} \right.\) 

   Vậy `x∈{1;-5}`

   `9)|x- 5|=10`

   `→` \(\left[ \begin{array}{l}x-5=10\\x-5=-10\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=15\\x=-5\end{array} \right.\) 

   Vậy `x∈{15;-5}`

   `10)|5- x|=2`

   `→` \(\left[ \begin{array}{l}5-x=2\\5-x=-2\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=3\\x=7\end{array} \right.\) 

   Vậy `x∈{3;7}`

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