Toán 1)(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3) giỏi toái đâu qua lẹ lào 24/07/2021 By Elliana 1)(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3) giỏi toái đâu qua lẹ lào
1) `(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3)` `=x^2+10x+25-4x(4x^2+12x+9)-(2x-1)(x^2-9)` `=x^2+10x+25-16x^3-48x^2-36x-2x^3+x^2+18x-9` `=-18x^3-46x^2-8x+16` Trả lời
`(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3)` `= x²+10x+25-4x(4x²+12x+9)-(2x-1)(x²-9)` `= x²+10x+25-16x³-48x²-36x-2x³+18x+x²-9` `=-18x³-46x³-8x+16` Xin hay nhất ! Trả lời
1)
`(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3)`
`=x^2+10x+25-4x(4x^2+12x+9)-(2x-1)(x^2-9)`
`=x^2+10x+25-16x^3-48x^2-36x-2x^3+x^2+18x-9`
`=-18x^3-46x^2-8x+16`
`(x+5)^2-4x.(2x+3)^2-(2x-1).(x+3).(x-3)`
`= x²+10x+25-4x(4x²+12x+9)-(2x-1)(x²-9)`
`= x²+10x+25-16x³-48x²-36x-2x³+18x+x²-9`
`=-18x³-46x³-8x+16`
Xin hay nhất !