x + 1/5=3/7 x – 3/4=1/2 -x – 9/2004=-1/2003 5/9-x=1/2004 23/08/2021 Bởi Natalia x + 1/5=3/7 x – 3/4=1/2 -x – 9/2004=-1/2003 5/9-x=1/2004
Đáp án: a, x + $\frac{1}{5}$ = $\frac{3}{7}$ ⇔ x = $\frac{3}{7}$ – $\frac{1}{5}$ ⇔ x =$\frac{15}{35}$ – $\frac{7}{35}$ ⇔ x = $\frac{8}{35}$ b, x- $\frac{3}{4}$ = $\frac{1}{2}$ ⇔ x = $\frac{1}{2}$ + $\frac{3}{4}$ ⇔ x = $\frac{5}{4}$ c, – x – $\frac{9}{2004}$ = $\frac{-1}{2003}$ ⇔ – x = $\frac{-1}{2003}$ + $\frac{9}{2004}$ ⇔ – x = $\frac{16023}{4014012}$ ⇔ x = $\frac{-16023}{4014012}$ d, $\frac{5}{9}$ – x = $\frac{1}{2004}$ ⇔ x = $\frac{5}{9}$ – $\frac{1}{2004}$ ⇔ x = $\frac{3337}{6012}$ Bình luận
Đáp án: Giải thích các bước giải: `x + 1/5=3/7` `x=3/7-1/5` `x=\frac{8}{35}` `x – 3/4=1/2` `x=\frac{1}{2}+\frac{3}{4}` `x=\frac{5}{4}` `-x – 9/2004=-1/2003` `-x=-\frac{1}{2003}+\frac{9}{2004}` `x=-\frac{16023}{4014012}` `5/9-x=1/2004` `x=\frac{5}{9}-\frac{1}{2004}` `x=\frac{3337}{6012}` Bình luận
Đáp án:
a, x + $\frac{1}{5}$ = $\frac{3}{7}$
⇔ x = $\frac{3}{7}$ – $\frac{1}{5}$
⇔ x =$\frac{15}{35}$ – $\frac{7}{35}$
⇔ x = $\frac{8}{35}$
b, x- $\frac{3}{4}$ = $\frac{1}{2}$
⇔ x = $\frac{1}{2}$ + $\frac{3}{4}$
⇔ x = $\frac{5}{4}$
c, – x – $\frac{9}{2004}$ = $\frac{-1}{2003}$
⇔ – x = $\frac{-1}{2003}$ + $\frac{9}{2004}$
⇔ – x = $\frac{16023}{4014012}$
⇔ x = $\frac{-16023}{4014012}$
d, $\frac{5}{9}$ – x = $\frac{1}{2004}$
⇔ x = $\frac{5}{9}$ – $\frac{1}{2004}$
⇔ x = $\frac{3337}{6012}$
Đáp án:
Giải thích các bước giải:
`x + 1/5=3/7`
`x=3/7-1/5`
`x=\frac{8}{35}`
`x – 3/4=1/2`
`x=\frac{1}{2}+\frac{3}{4}`
`x=\frac{5}{4}`
`-x – 9/2004=-1/2003`
`-x=-\frac{1}{2003}+\frac{9}{2004}`
`x=-\frac{16023}{4014012}`
`5/9-x=1/2004`
`x=\frac{5}{9}-\frac{1}{2004}`
`x=\frac{3337}{6012}`