1/5x³y.(-5x⁴yz³)² Mn giải giúp mình vs ạ^^ 03/10/2021 Bởi Delilah 1/5x³y.(-5x⁴yz³)² Mn giải giúp mình vs ạ^^
$\frac{1}{5}$x³y . ( -5$x^{4}$yz³ ) ² = $\frac{1}{5}$x³y . ( -25$x^{8}$y²$z^{6}$ ) = [ $\frac{1}{5}$ . ( -25 ) ] . (x³$x^{8}$ ) . ( yy² ) . $z^{6}$ = 5$x^{11}$$y^{3}$$z^{6}$ Bình luận
Đáp án: `\frac{1}{5}x^3y .( -5x^4yz^3)^2` ` = \frac{1}{5}x^3y . 25x^{8}y^2z^6` ` = (\frac{1}{5}.25) . (x^3 . x^{8}) . (y. y^2). z^6` ` = 5.x^{11}.y^3.z^6` Bình luận
$\frac{1}{5}$x³y . ( -5$x^{4}$yz³ ) ²
= $\frac{1}{5}$x³y . ( -25$x^{8}$y²$z^{6}$ )
= [ $\frac{1}{5}$ . ( -25 ) ] . (x³$x^{8}$ ) . ( yy² ) . $z^{6}$
= 5$x^{11}$$y^{3}$$z^{6}$
Đáp án:
`\frac{1}{5}x^3y .( -5x^4yz^3)^2`
` = \frac{1}{5}x^3y . 25x^{8}y^2z^6`
` = (\frac{1}{5}.25) . (x^3 . x^{8}) . (y. y^2). z^6`
` = 5.x^{11}.y^3.z^6`