1) |8-2x|=2
2) x-2 x-3 1
_____ + _____ = _______
x-3 3x 3x²-9x
1) |8-2x|=2
2) x-2 x-3 1
_____ + _____ = _______
x-3 3x 3x²-9x
1)
|8-2x|=2
⇔\(\left[ \begin{array}{l}8-2x=2\\8-2x=-2\end{array} \right.\)
⇔\(\left[ \begin{array}{l}2x=6\\2x=10\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=3\\x=5\end{array} \right.\)
2) Đk: x$\neq$0, x$\neq$ 3
$\frac{x-2}{x-3}$ + $\frac{x-3}{3x}$ =$\frac{1}{3x²-9x}$
⇒3x (x-2)+(x-3)²=1
⇔3x² -6x+x²-6x+9=1
⇔4x²-12x+8=0
⇔x²-3x+2=0
⇔x²-2x-x+2=0
⇔x(x-2)-(x-2)=0
⇔(x-2)(x-1)=0
⇔\(\left[ \begin{array}{l}x-2=0\\x-1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=2\\x=1\end{array} \right.\)
em chỉ làm dc 1 câu th ạ,chúc a/c học tốt