1.(x ²-9) ²+12x(x-3) ² 2.24ab(a ² -b ²)-6(a ³+a ²*b-b ³)+9(a ²-)b ² 3.x ³(x ²+1) ²-9x 4.x ∧6 ↓y-x ∧4 ↓y ³-x ³y ∧4 ↓+xy ∧6 5.x ³y ³ z ³+x ²y ²z ²-xyz-

1.(x ²-9) ²+12x(x-3) ²
2.24ab(a ² -b ²)-6(a ³+a ²*b-b ³)+9(a ²-)b ²
3.x ³(x ²+1) ²-9x
4.x ∧6 ↓y-x ∧4 ↓y ³-x ³y ∧4 ↓+xy ∧6
5.x ³y ³ z ³+x ²y ²z ²-xyz-1

0 bình luận về “1.(x ²-9) ²+12x(x-3) ² 2.24ab(a ² -b ²)-6(a ³+a ²*b-b ³)+9(a ²-)b ² 3.x ³(x ²+1) ²-9x 4.x ∧6 ↓y-x ∧4 ↓y ³-x ³y ∧4 ↓+xy ∧6 5.x ³y ³ z ³+x ²y ²z ²-xyz-”

  1. Đáp án:

    `1)(x^2-9)+12x(x-3)^2=(x-3)(12x^2-35x+3).`

    `2)24ab(a^2 -b^2)-6(a^3+a^2b-b^3)+9(a^2-b^2=3(8a^3b-8ab^3-2a^3-2a^2b+2b^3+3a^2-3b^2).`

    `3)x^3(x^2+1)^2-9x=x(x^3+x+3)(x^2+x-3).`

    `4)x^6y-x^4y^3-x^3y^4+xy^6=xy(x+y)(x-y)^2(x^2+xy+y^2).`

    `5)x^3y^3z^3+x^2y^2z^2-xyz-1=(xyz+1)^2(xyz-1).`

    Giải thích các bước giải.

    `1)(x^2-9)+12x(x-3)^2`

    `=(x-3)(x+3)+12x(x-3)(x-3)`

    `=(x-3)[(x+3)+12x(x-3)]`

    `=(x-3)(12x^2-35x+3).`

    `2)24ab(a^2 -b^2)-6(a^3+a^2b-b^3)+9(a^2-b^2)`

    `=3[8ab(a^2 -b^2)-2(a^3+a^2b-b^3)+3(a^2-b^2)]`

    `=3(8a^3b-8ab^3-2a^3-2a^2b+2b^3+3a^2-3b^2).`

    `3)x^3(x^2+1)^2-9x`

    `=x[x^2(x^2+1)^2-9]`

    `=x{[x(x^2+x)]^2-3^2}`

    `=x[(x^3+x)^3-3^2]`

    `=x(x^3+x+3)(x^2+x-3).`

    `4)x^6y-x^4y^3-x^3y^4+xy^6`

    `=(x^6y+xy^6)-(x^4y^3+x^3y^4)`

    `=xy(x^5+y^5)-x^3y^3(x+y)`

    `=xy[x^5+y^5-x^2y^2(x+y)]`

    `=xy(x^5+y^5-x^3y^2-x^2y^3)`

    `=xy[(x^5-x^3y^2)+(y^5-x^2y^3)]`

    `=xy[x^3(x^2-y^2)+y^3(y^2-x^2)]`

    `=xy(x^2-y^2)(x^3-y^3)`

    `=xy(x+y)(x-y)(x-y)(x^2+xy+y^2)`

    `=xy(x+y)(x-y)^2(x^2+xy+y^2).`

    `5)x^3y^3z^3+x^2y^2z^2-xyz-1`

    `=(x^3y^3z^3+x^2y^2z^2)-(xyz+1)`

    `=x^2y^2(xyz+1)-(xyz+1)`

    `=(xyz+1)(x^2y^2z^2-1)`

    `=(xyz+1)(xyz+1)(xyz-1)`

    `=(xyz+1)^2(xyz-1).`

     

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