1. a) -a – (b – a – c) b) -(a – c) – (a – b + c) c) b – (b + a + c) d) -(a – b + c) – (a + b + c) 02/07/2021 Bởi Everleigh 1. a) -a – (b – a – c) b) -(a – c) – (a – b + c) c) b – (b + a + c) d) -(a – b + c) – (a + b + c)
Đáp án: Giải thích các bước giải: `a) -a – (b – a – c)` `= -a-b+a+c` `= c-b` `b) -(a – c) – (a – b + c)` `= -a+c-a+b-c` `= -2a+b` `c) b – (b + a + c)` `= b-b-a-c` `= -a-c` `d) -(a – b + c) – (a + b + c)` `= -a+b-c-a-b-c` `= -2a-2c` Bình luận
Đáp án: a, `-a – (b – a – c)` `= -a – b + a + c` `=(-a + a) + c – b` `= c – b` b, `-(a – c) – (a – b + c)` `= -a + c – a + b – c` `=(-a – a) + ( c – c) + b` `= -2a + b` c, `b – (b + a + c)` `= b – b – a – c` `=( b – b) – a – c` `=-a – c` d, `-(a – b + c) – (a + b + c)` ` = -a + b – c – a – b – c` ` = (-a – a) + (b – b) – (c + c)` ` = -2a – 2c` Bình luận
Đáp án:
Giải thích các bước giải:
`a) -a – (b – a – c)`
`= -a-b+a+c`
`= c-b`
`b) -(a – c) – (a – b + c)`
`= -a+c-a+b-c`
`= -2a+b`
`c) b – (b + a + c)`
`= b-b-a-c`
`= -a-c`
`d) -(a – b + c) – (a + b + c)`
`= -a+b-c-a-b-c`
`= -2a-2c`
Đáp án:
a, `-a – (b – a – c)`
`= -a – b + a + c`
`=(-a + a) + c – b`
`= c – b`
b, `-(a – c) – (a – b + c)`
`= -a + c – a + b – c`
`=(-a – a) + ( c – c) + b`
`= -2a + b`
c, `b – (b + a + c)`
`= b – b – a – c`
`=( b – b) – a – c`
`=-a – c`
d, `-(a – b + c) – (a + b + c)`
` = -a + b – c – a – b – c`
` = (-a – a) + (b – b) – (c + c)`
` = -2a – 2c`