1 ax+ b √x= 2 x+ √x= 3 2x -4 √x= 4 4x+ 6 √x= 5 x √x +2 x= 6 2 x √x -6= 7x- √x- √x= 8 x- √x- √x+x-1= 9 x+ √x-2= 10 2 x- √x -1 = 11x+ √x -6 = 12 x +

0 bình luận về “1 ax+ b √x= 2 x+ √x= 3 2x -4 √x= 4 4x+ 6 √x= 5 x √x +2 x= 6 2 x √x -6= 7x- √x- √x= 8 x- √x- √x+x-1= 9 x+ √x-2= 10 2 x- √x -1 = 11x+ √x -6 = 12 x +”

1. 1. $ax+b\sqrt{x}=\sqrt{x}(a\sqrt{x}+b)$

   2. $x+\sqrt{x}=\sqrt{x}(\sqrt{x}+1)$

   3. $2x-4\sqrt{x}=2\sqrt{x}(\sqrt{x}-2)$

   4. $4x+6\sqrt{x}=2\sqrt{x}(2\sqrt{x}+3)$

   5. $x\sqrt{x}+2x=x(\sqrt{x}+2)$

   6. $2x\sqrt{x}-6=2(x\sqrt{x}-3)$

   7. $x-\sqrt{x}-\sqrt{x}=x-2\sqrt{x}=\sqrt{x}(\sqrt{x}-2)$

   8. $x-\sqrt{x}-\sqrt{x}+x-1=2x-2\sqrt{x}-1$

   9. $x+\sqrt{x}-2=x-\sqrt{x}+2\sqrt{x}-2=\sqrt{x}(\sqrt{x}-1)+2(\sqrt{x}-1)=(\sqrt{x}-1)(\sqrt{x}+2)$

   10. $2x-\sqrt{x}-1=2x-2\sqrt{x}+\sqrt{x}-1=2\sqrt{x}(\sqrt{x}-1)+(\sqrt{x}-1)=(\sqrt{x}-1)(2\sqrt{x}+1)$

   11. $x+\sqrt{x}-6=x-2\sqrt{x}+3\sqrt{x}-6=\sqrt{x}(\sqrt{x}-2)+3(\sqrt{x}-2)=(\sqrt{x}-2)(\sqrt{x}+3)$

   12. $x+2\sqrt{x}-15=x-3\sqrt{x}+5\sqrt{x}-15=\sqrt{x}(\sqrt{x}-3)+5(\sqrt{x}-3)=(\sqrt{x}-3)(\sqrt{x}+5)$

   13. $x+\sqrt{x}-6$ giống câu 11.

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