1. Hoàn thành chuỗi pứ: ch4 >> c2h2 >> c2h4 >> c2h5cl >> c2h5oh >> ch3cho >> ch3cooh
2. Từ benzen, nhôm cacbua và các chất vô cơ cần thiết, viết ptpu octo-brombenzoic
1. Hoàn thành chuỗi pứ: ch4 >> c2h2 >> c2h4 >> c2h5cl >> c2h5oh >> ch3cho >> ch3cooh
2. Từ benzen, nhôm cacbua và các chất vô cơ cần thiết, viết ptpu octo-brombenzoic
1.
$2CH_4\xrightarrow{{1500^oC}} C_2H_2+3H_2$
$C_2H_2+H_2\xrightarrow{{Pd/PbCO_3, t^o}} C_2H_4$
$C_2H_4+HCl\to C_2H_5Cl$
$C_2H_5Cl+NaOH\xrightarrow{{t^o}} C_2H_5OH+NaCl$
$C_2H_5OH+CuO\xrightarrow{{t^o}} CH_3CHO+Cu+H_2O$
$CH_3CHO+Br_2+H_2O\to CH_3COOH+2HBr$
2.
$Al_4C_3+12H_2O\to 4Al(OH)_3+3CH_4$
$CH_4+Cl_2\xrightarrow{{as}} CH_3Cl+HCl$
$C_6H_6+CH_3Cl\xrightarrow{{AlCl_3, t^o}} C_6H_5CH_3+HCl$
$C_6H_5CH_3+Br_2\xrightarrow{{Fe, t^o}} HBr+o-C_6H_4BrCH_3$
$o-BrC_6H_4CH_3+2KMnO_4\xrightarrow{{t^o}}o-BrC_6H_4COOK+2MnO_2+KOH+H_2O$
$o-BrC_6H_4COOK+HCl\to KCl+o-BrC_6H_4COOH$ (axit ortho-brombenzoic)
1.
$C2H_4 \xrightarrow{1500^oC, \text{làm lạnh nhanh}}C_2H_2+3H_2$
$C_2H_2+H_2\xrightarrow{Pd/PdCO_3,t^o} C_2H_4$
$C_2H_4+HCl\xrightarrow{}C_2H_5Cl$
$C_2H_5Cl+KOH\xrightarrow{}C_2H_5OH+KCl$
$C_2H_5OH+CuO\xrightarrow{t^o}CH_3CHO+Cu+H_2O$
$CH_3CHO+\dfrac{1}{2}O_2\xrightarrow{t^o,xt}CH_3COOH$
2.
$C_6H_6+CH_3Cl\xrightarrow{AlCl_3}C_6H_5CH_3+HCl$
$C_6H_5CH_3+Br_2\xrightarrow{t^o, Fe}CH_3C_6H_4Br+HBr$
$5CH_3C_6H_4Br+6KMnO_4+9H_2SO_4\xrightarrow{}5HOOCC_6H_4Br+3K_2SO_4+6MnSO_4+14H_2O$