1,nacl–>nước gia ven-> cl2_>hcl->agcl->ag 2,kmno4 ->cl2 ->nacl->cl2->fecl3->fe(oh)3->fe203-> fe(no3)3 3,hc->cl2-> fecl3->nacl->hcl->cucl2->agcl->ag 4

1,nacl–>nước gia ven-> cl2_>hcl->agcl->ag
2,kmno4 ->cl2 ->nacl->cl2->fecl3->fe(oh)3->fe203-> fe(no3)3
3,hc->cl2-> fecl3->nacl->hcl->cucl2->agcl->ag
4,f2->caf2->hf->sif4
5,caco3->cacl2->nacl->naoh->naclo
6,kmno4_>cl2->hclo->hcl->mgcl2->agcl->cl2->br2->kbr> kcl->hcl
7,naoh->nacl->hcl->cl2->hcl->cucl2->cu(oh)2->cuo->cucl2->kcl_>cl2

0 bình luận về “1,nacl–>nước gia ven-> cl2_>hcl->agcl->ag 2,kmno4 ->cl2 ->nacl->cl2->fecl3->fe(oh)3->fe203-> fe(no3)3 3,hc->cl2-> fecl3->nacl->hcl->cucl2->agcl->ag 4”

  1. Đáp án:

    Bạn tham khảo lời giải ở dưới nhé!!!

    Giải thích các bước giải:

    1,

    \(\begin{array}{l}
    2NaCl + 2{H_2}O \to 2NaOH + {H_2} + C{l_2}\\
    2NaOH + C{l_2} \to NaCl + NaClO + {H_2}O\\
    NaClO + 2HCl \to NaCl + C{l_2} + {H_2}O\\
    C{l_2} + {H_2} \to 2HCl\\
    HCl + AgN{O_3} \to AgCl + HN{O_3}\\
    2AgCl \to 2Ag + C{l_2}
    \end{array}\)

    \(\begin{array}{l}
    2,\\
    2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
    2Na + C{l_2} \to 2NaCl\\
    2NaCl + 2{H_2}O \to 2NaOH + {H_2} + C{l_2}\\
    2Fe + 3C{l_2} \to 2FeC{l_3}\\
    FeC{l_3} + 3NaOH \to Fe{(OH)_3} + 3NaCl\\
    2Fe{(OH)_3} \to F{e_2}{O_3} + 3{H_2}O\\
    F{e_2}{O_3} + 6HN{O_3} \to 2Fe{(N{O_3})_3} + 3{H_2}O\\
    3,\\
    2HCl \to {H_2} + C{l_2}\\
    2Fe + 3C{l_2} \to 2FeC{l_3}\\
    FeC{l_3} + 3NaOH \to Fe{(OH)_3} + 3NaCl\\
    2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
    CuO + 2HCl \to CuC{l_2} + {H_2}O\\
    CuC{l_2} + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2AgCl\\
    2AgCl \to 2Ag + C{l_2}\\
    4,\\
    {F_2} + Ca \to Ca{F_2}\\
    Ca{F_2} + {H_2}S{O_4} \to CaS{O_4} + 2HF\\
    Si{O_2} + 4HF \to Si{F_4} + 2{H_2}O\\
    5,\\
    CaC{O_3} + 2HCl \to CaC{l_2} + C{O_2} + {H_2}O\\
    CaC{l_2} + N{a_2}S{O_4} \to CaS{O_4} + 2NaCl\\
    2NaCl + 2{H_2}O \to 2NaOH + {H_2} + C{l_2}\\
    2NaOH + C{l_2} \to NaCl + NaClO + {H_2}O\\
    6,\\
    2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
    C{l_2} + {H_2}O \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over
    {\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} HCl + HClO\\
    HClO \to HCl + {O_2}\\
    2HCl + Mg \to MgC{l_2} + {H_2}\\
    MgC{l_2} + 2AgN{O_3} \to 2AgCl + Mg{(N{O_3})_2}\\
    2AgCl \to 2Ag + C{l_2}\\
    2KBr + C{l_2} \to 2KCl + B{r_2}\\
    2K + B{r_2} \to 2KBr\\
    2KBr + C{l_2} \to 2KCl + B{r_2}\\
    2KCl + {H_2}S{O_4} \to {K_2}S{O_4} + 2HCl
    \end{array}\)

    7,

    \(\begin{array}{l}
    NaOH + HCl \to NaCl + {H_2}O\\
    2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
    2HCl \to {H_2} + C{l_2}\\
    {H_2} + C{l_2} \to 2HCl\\
    CuO + 2HCl \to CuC{l_2} + {H_2}O\\
    CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
    Cu{(OH)_2} \to CuO + {H_2}O\\
    CuO + 2HCl \to CuC{l_2} + {H_2}O\\
    CuC{l_2} + 2KOH \to Cu{(OH)_2} + 2KCl\\
    2KCl \to 2K + C{l_2}
    \end{array}\)

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