1. Tìm x a) (x-1)(x^2+x+1)-(2+x)(4-2x+x^2)=3x b) 8(x- 1/2)(x^2+1/2x+1/4)-x(1+8x^2)+2=0 17/08/2021 Bởi Valerie 1. Tìm x a) (x-1)(x^2+x+1)-(2+x)(4-2x+x^2)=3x b) 8(x- 1/2)(x^2+1/2x+1/4)-x(1+8x^2)+2=0
`a,(x-1)(x^2+x+1)-(2+x)(4-2x+x^2)=3x` `⇔x^3-1-8-x^3=3x` `⇔3x=-9` `⇔x=-3` `b,8(x-1/2)(x^2+1/2 x+1/4)-x(1+8x^2)+2=0` `⇔8(x^3-1/8)-x-8x^3+2=0` `⇔8x^3-1-x-8x^3+2=0` `⇔-x=-1` `⇔x=1` Bình luận
`a,(x-1)(x^2+x+1)-(2+x)(4-2x+x^2)=3x`
`⇔x^3-1-8-x^3=3x`
`⇔3x=-9`
`⇔x=-3`
`b,8(x-1/2)(x^2+1/2 x+1/4)-x(1+8x^2)+2=0`
`⇔8(x^3-1/8)-x-8x^3+2=0`
`⇔8x^3-1-x-8x^3+2=0`
`⇔-x=-1`
`⇔x=1`