1. Tìm x:
a) (x+1) mũ 5 = 32
b) (x – 140) :7 = 3 mũ 3 – 2 mũ ba x 3
c) 5 x 2 mũ 2 + (x +3) = 5 mũ 3
1. Tìm x: a) (x+1) mũ 5 = 32 b) (x – 140) :7 = 3 mũ 3 – 2 mũ ba x 3 c) 5 x 2 mũ 2 + (x +3) = 5 mũ 3
By Gianna
By Gianna
1. Tìm x:
a) (x+1) mũ 5 = 32
b) (x – 140) :7 = 3 mũ 3 – 2 mũ ba x 3
c) 5 x 2 mũ 2 + (x +3) = 5 mũ 3
bn tham khảo nha
a,$(x+1)^{5 }$ = 32
$(x+1)^{5}$ = $2^{5}$
⇒x + 1 = 2
x = 1
b ) ( x – 140 ) : 7 =$3^{3}$ -$2^{3}$ x 3
( x – 140 ) : 7 = 27 – 8 x 3
( x – 140 ) : 7 = 27 – 24
( x – 140 ) : 7 = 3
x – 140 = 3 x 7
x – 140 = 21
x = 21 + 140
x = 161
c ) 5 x $2^{2}$ + ( x + 3 ) = $5^{3}$
5 x 4 + x + 3 = 125
20 + x + 3 = 125
23 + x = 125
x = 125 – 23
x = 102
chúc bn hc tốt
cho mk xin hay nhất nha
Đáp án: a ) x = 1 ; b ) x = 161 ; c ) x = 102
Giải thích các bước giải:
a ) $(x+1)^{5}$ = 32
→ $(x+1)^{5}$ = $2^{5}$
→ x + 1 = 2
→ x = 1
b ) ( x – 140 ) : 7 = $3^{3}$ – $2^{3}$ x 3
( x – 140 ) : 7 = 27 – 8 x 3
( x – 140 ) : 7 = 27 – 24
( x – 140 ) : 7 = 3
x – 140 = 3 x 7
x – 140 = 21
x = 21 + 140
x = 161
c ) 5 x $2^{2}$ + ( x + 3 ) = $5^{3}$
5 x 4 + x + 3 = 125
20 + x + 3 = 125
23 + x = 125
x = 125 – 23
x = 102