1.tim x biet (7x – 11) mũ 3=2mũ5 X 5mũ2 + 200 2.tinh (- 43 ) + ( – 19 ) 24/11/2021 Bởi Ximena 1.tim x biet (7x – 11) mũ 3=2mũ5 X 5mũ2 + 200 2.tinh (- 43 ) + ( – 19 )
1. `(7x – 11)³ = 2^{5} X 5² + 200` `⇔ (7x – 11)³ = 32 X 25 + 200` `⇔ (7x – 11)³ = 800 + 200` `⇔ (7x – 11)³ = 1000` `⇔ 7x – 11 = ∛1000` `⇔ 7x – 11 = 10` `⇔ 7x = 10 + 11` `⇔ 7x = 21` `⇔ x = 21 : 7` `⇔ x = 3` Vậy x = 3 2. (-43) + (-19) = (-43) – 19 = -62 Bình luận
`(7x – 11)^3=2^5 × 5^2 + 200` `(7x – 11)^3=32 × 25 + 200` `(7x – 11)^3= 800 + 200` `(7x – 11)^3= 1000` ` (7x – 11)^3= 10^3` `7x – 11 = 10` `7x = 10 + 11` `7x = 21` `x = 3` 2. Tính (-43) + (-19) = – ( 43 + 19 ) = -62 Bình luận
1.
`(7x – 11)³ = 2^{5} X 5² + 200`
`⇔ (7x – 11)³ = 32 X 25 + 200`
`⇔ (7x – 11)³ = 800 + 200`
`⇔ (7x – 11)³ = 1000`
`⇔ 7x – 11 = ∛1000`
`⇔ 7x – 11 = 10`
`⇔ 7x = 10 + 11`
`⇔ 7x = 21`
`⇔ x = 21 : 7`
`⇔ x = 3`
Vậy x = 3
2.
(-43) + (-19) = (-43) – 19 = -62
`(7x – 11)^3=2^5 × 5^2 + 200`
`(7x – 11)^3=32 × 25 + 200`
`(7x – 11)^3= 800 + 200`
`(7x – 11)^3= 1000`
` (7x – 11)^3= 10^3`
`7x – 11 = 10`
`7x = 10 + 11`
`7x = 21`
`x = 3`
2. Tính
(-43) + (-19) = – ( 43 + 19 ) = -62