1. Tìm lim (1 – n^2) / (2n^2 + 1) 2. Tìm lim (4n + 2018) / (2n + 1)

Đáp án:

$\begin{array}{l}
1)\lim \dfrac{{1 – {n^2}}}{{2{n^2} + 1}} = \lim \dfrac{{\dfrac{1}{{{n^2}}} – 1}}{{2 + \dfrac{1}{{{n^2}}}}} = \dfrac{{ – 1}}{2}\\
2)\lim \dfrac{{4n + 2018}}{{2n + 1}} = \lim \dfrac{{4 + \dfrac{{2018}}{n}}}{{2 + \dfrac{1}{n}}} = \dfrac{4}{2} = 2
\end{array}$