1-tính a) (9/3) mũ 2 nhân x=(4/3) mũ 4 b) (2/3) mũ 5 chia x=(2/3) mũ 3 c) 3 mũ x + 3 mũ x+1=810

0 bình luận về “1-tính a) (9/3) mũ 2 nhân x=(4/3) mũ 4 b) (2/3) mũ 5 chia x=(2/3) mũ 3 c) 3 mũ x + 3 mũ x+1=810”

1. Phần c nó cứ sao sao ý bạn !

   a) `(9/3)^2 . x = ( 4/3)^4`

   `=> 81/9 . x = 256/81`

   `=> x = 256/81 : 81/9`

   `=> x = 256/81 . 9/81`

   `=> x = 256/729`

   Vậy `x = 256/729`

   b) `(2/3)^5 : x = ( 2/3)^3`

   `=> x = ( 2/3)^5 : (2/3)^3`

   `=> x = (2/3)^2`

   `=> x = 4/9`

   Vậy `x = 4/9`

   @-@

    

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2. =))

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