Toán 1. Tính giá trị của x, biết: 3.(2x-3)^2=48 01/07/2021 By Caroline 1. Tính giá trị của x, biết: 3.(2x-3)^2=48
Đáp án: \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\) Giải thích các bước giải: 3 . $(2x-3)^{2}$ = 48 → $(2x-3)^{2}$ = 16 → \(\left[ \begin{array}{l}(2x-3)^2=4^2\\(2x-3)^2=-4^2\end{array} \right.\) → \(\left[ \begin{array}{l}2x-3=4\\2x-3=-4\end{array} \right.\) → \(\left[ \begin{array}{l}2x=7\\2x=-1\end{array} \right.\) → \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\) Trả lời
`3.(2x – 3)^2 = 48` `<=> (2x – 3)^2 = 16` `<=> |2x – 3| = 4` `<=>` \(\left[ \begin{array}{l}2x – 3 = 4\\2x – 3 = -4\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x = \dfrac{7}{2}\\x = -\dfrac{1}{2}\end{array} \right.\) Trả lời
Đáp án: \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\)
Giải thích các bước giải:
3 . $(2x-3)^{2}$ = 48
→ $(2x-3)^{2}$ = 16
→ \(\left[ \begin{array}{l}(2x-3)^2=4^2\\(2x-3)^2=-4^2\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x-3=4\\2x-3=-4\end{array} \right.\)
→ \(\left[ \begin{array}{l}2x=7\\2x=-1\end{array} \right.\)
→ \(\left[ \begin{array}{l}x=\frac{7}{2}\\x=\frac{-1}{2}\end{array} \right.\)
`3.(2x – 3)^2 = 48`
`<=> (2x – 3)^2 = 16`
`<=> |2x – 3| = 4`
`<=>` \(\left[ \begin{array}{l}2x – 3 = 4\\2x – 3 = -4\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = \dfrac{7}{2}\\x = -\dfrac{1}{2}\end{array} \right.\)