|x+13|-|-10|=-8+2
|x-11|-(-5+6)=-|-5|
|x+11|-|-3|+|-5|=8
|x-3|-(5-7+|-3|=|5-7|
5-|x-1|=3-|4+5-7|
51-|x-1|=-(4-51+3|
-12+3-|x+2|=7-12
14-(5-6)-|x-3|=14
23-(7-4)-|x+7|=1-(-23)
Thanks
|x+13|-|-10|=-8+2
|x-11|-(-5+6)=-|-5|
|x+11|-|-3|+|-5|=8
|x-3|-(5-7+|-3|=|5-7|
5-|x-1|=3-|4+5-7|
51-|x-1|=-(4-51+3|
-12+3-|x+2|=7-12
14-(5-6)-|x-3|=14
23-(7-4)-|x+7|=1-(-23)
Thanks
`a)|x+13|-|-10|=-8+2`
`→|x+13|-10=-6`
`→|x+13|=-6+10`
`→|x+13|=4`
`→` \(\left[ \begin{array}{l}x+13=4\\x+13=-4\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=-9\\x=-17\end{array} \right.\)
Vậy `x∈{-9;-17}`
`b)|x-11|-(-5+6)=-|-5|`
`→|x-11|-1=-5`
`→|x-11|=-4`
`|x-11|≥0→x∈∅`
Vậy `x∈∅`
`c)|x+11|-|-3|+|-5|=8`
`→|x+11|-3+5=8`
`→|x+11|=8+3-5`
`→|x+11|=6`
`→` \(\left[ \begin{array}{l}x+11=6\\x+11=-6\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=-5\\x=-17\end{array} \right.\)
Vậy `x∈{-5;-17}`
`d)|x-3|-(5-7+|-3|=|5-7|`
`→|x-3|-1=2`
`→|x-3|=3`
`→` \(\left[ \begin{array}{l}x-3=3\\x-3=-3\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=6\\x=0\end{array} \right.\)
Vậy `x∈{6;0}`
`e)5-|x-1|=3-|4+5-7|`
`→5-|x-1|=1`
`→|x-1|=4`
`→` \(\left[ \begin{array}{l}x-1=4\\x-1=-4\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\)
Vậy `x∈{5;-3}`
`f)51-|x-1|=-(4-51+3)`
`→51-|x-1|=44`
`→|x-1|=7`
`→` \(\left[ \begin{array}{l}x-1=7\\x-1=-7\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=8\\x=-6\end{array} \right.\)
Vậy `x∈{8;-6}`
`g)-12+3-|x+2|=7-12`
`→-9-|x+2|=-5`
`→|x+1|=-9-(-5)`
`→|x+1|=-4`
`|x+1|≥0→x∈∅`
`h)14-(5-6)-|x-3|=14`
`→15-|x-3|=14`
`→|x-3|=15-14`
`→|x-3|=1`
`→` \(\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\)
Vậy `x∈{4;2}`
`i)23-(7-4)-|x+7|=1-(-23)`
`→20-|x+7|=24`
`→|x+7|=20-24`
`→|x+7|=-4`
`|x+7|≥0→x∈∅`