/x-14/lớn hơn 10 câu tìm x nha giúp mik vs mn 28/08/2021 Bởi Serenity /x-14/lớn hơn 10 câu tìm x nha giúp mik vs mn
$|x-14| > 10$ $⇒$ \(\left[ \begin{array}{l}x-14 > 10\\x-14 < -10\end{array} \right.\) $⇒$ \(\left[ \begin{array}{l}x> 24\\x < 4\end{array} \right.\) $⇒$ $x$ $∈$ `{……;1;2;3;25;26;…….}` Vậy $x$ $∈$ `{……;1;2;3;25;26;…….}` Bình luận
`|x-14|>10` \(⇒\left[ \begin{array}{l}x-14>10\\14-x>10\end{array}\right.\) \(⇒\left[ \begin{array}{l}x>24\\x<4\end{array}\right.\) `⇒x∈{…;1;2;3;25;26;27;…}` Bình luận
$|x-14| > 10$
$⇒$ \(\left[ \begin{array}{l}x-14 > 10\\x-14 < -10\end{array} \right.\)
$⇒$ \(\left[ \begin{array}{l}x> 24\\x < 4\end{array} \right.\)
$⇒$ $x$ $∈$ `{……;1;2;3;25;26;…….}`
Vậy $x$ $∈$ `{……;1;2;3;25;26;…….}`
`|x-14|>10`
\(⇒\left[ \begin{array}{l}x-14>10\\14-x>10\end{array}\right.\)
\(⇒\left[ \begin{array}{l}x>24\\x<4\end{array}\right.\)
`⇒x∈{…;1;2;3;25;26;27;…}`