15. C4h10 -> c2h6 -> c2h5cl 16. Ch3coona -> ch4 -> ch3cl -> ch2cl2 -> chcl3 -> ccl4 11/08/2021 Bởi Liliana 15. C4h10 -> c2h6 -> c2h5cl 16. Ch3coona -> ch4 -> ch3cl -> ch2cl2 -> chcl3 -> ccl4
15. $C_4H_{10}\buildrel{{t^o, xt}}\over\longrightarrow C_2H_6+ C_2H_4$ $C_2H_6+Cl_2\buildrel{{as}}\over\to C_2H_5Cl+ HCl$ 16. $CH_3COONa+NaOH\buildrel{{CaO, t^o}}\over\longrightarrow CH_4+Na_2CO_3$ $CH_4+Cl_2\buildrel{{as}}\over\longrightarrow CH_3Cl+HCl$ $CH_3Cl+Cl_2\buildrel{{as}}\over\longrightarrow CH_2Cl_2+HCl$ $CH_2Cl_2+Cl_2 \buildrel{{as}}\over\longrightarrow CHCl_3+HCl$ $CHCl_3+Cl_2 \buildrel{{as}}\over\longrightarrow CCl_4+HCl$ Bình luận
Giải thích các bước giải: 15. $C_4H_{10}\xrightarrow{t^o,xt}C_2H_4↑+C_2H_6↑$ $C_2H_6+Cl_2\xrightarrow{As}C_2H_5Cl+HCl$ 16. $CH_3COONa+NaOH\xrightarrow{t^o,CaO}Na_2CO_3+CH_4↑$ $CH_4+Cl_2\xrightarrow{As}CH_3Cl+HCl$ $CH_3Cl+Cl_2\xrightarrow{As}CH_2Cl_2+HCl$ $CH_2Cl_2+Cl_2\xrightarrow{As}CHCl_3+HCl$ $CHCl_3+Cl_2\xrightarrow{As}CCl_4+HCl$ Bình luận
15.
$C_4H_{10}\buildrel{{t^o, xt}}\over\longrightarrow C_2H_6+ C_2H_4$
$C_2H_6+Cl_2\buildrel{{as}}\over\to C_2H_5Cl+ HCl$
16.
$CH_3COONa+NaOH\buildrel{{CaO, t^o}}\over\longrightarrow CH_4+Na_2CO_3$
$CH_4+Cl_2\buildrel{{as}}\over\longrightarrow CH_3Cl+HCl$
$CH_3Cl+Cl_2\buildrel{{as}}\over\longrightarrow CH_2Cl_2+HCl$
$CH_2Cl_2+Cl_2 \buildrel{{as}}\over\longrightarrow CHCl_3+HCl$
$CHCl_3+Cl_2 \buildrel{{as}}\over\longrightarrow CCl_4+HCl$
Giải thích các bước giải:
15.
$C_4H_{10}\xrightarrow{t^o,xt}C_2H_4↑+C_2H_6↑$
$C_2H_6+Cl_2\xrightarrow{As}C_2H_5Cl+HCl$
16.
$CH_3COONa+NaOH\xrightarrow{t^o,CaO}Na_2CO_3+CH_4↑$
$CH_4+Cl_2\xrightarrow{As}CH_3Cl+HCl$
$CH_3Cl+Cl_2\xrightarrow{As}CH_2Cl_2+HCl$
$CH_2Cl_2+Cl_2\xrightarrow{As}CHCl_3+HCl$
$CHCl_3+Cl_2\xrightarrow{As}CCl_4+HCl$