17+x-(352-400)=-32 2130-(x+130)+72=-64 /x/-5=-1 /x+2/-13=-1 135-/9-x/=35 //x-5/-3/=9 12/11/2021 Bởi Adeline 17+x-(352-400)=-32 2130-(x+130)+72=-64 /x/-5=-1 /x+2/-13=-1 135-/9-x/=35 //x-5/-3/=9
Đáp án: , Giải thích các bước giải: `a,17+x-(352-400)=-32` `⇔x-(-48)=-32-17` `⇔x+48=-49` `⇔x=-49-48` `⇔x=-97` Vậy `x=-97` , `b,2130-(x+130)+72=-64` `⇔2130-x-130+72=-64` `⇔-x=-64-2130+130-72` `⇔-x=-2136` `⇔x=2136` Vậy `x=2136` , `c,|x|-5=-1` `⇔|x|=-1+5` `⇔|x|=4` \(⇔\left[ \begin{array}{l}x=4\\x=-4\end{array} \right.\) Vậy `x=4` hoặc `x=-4` , `d,|x+2|-13=-1` `⇔|x+2|=-1+13` `⇔|x+2|=12` \(⇔\left[ \begin{array}{l}x+2=12\\x+2=-12\end{array} \right.\) \(⇔\left[ \begin{array}{l}x=12-2\\x=-12-2\end{array} \right.\) \(⇔\left[ \begin{array}{l}x=10\\x=-14\end{array} \right.\) Vậy `x=10` hoặc `x=-14` , `e,135-|9-x|=35` `⇔|9-x|=135-35` `⇔|9-x|=100` \(⇔\left[ \begin{array}{l}9-x=100\\9-x=-100\end{array} \right.\) \(⇔\left[ \begin{array}{l}-x=100-9\\-x=-100-9\end{array} \right.\) \(⇔\left[ \begin{array}{l}-x=91\\-x=-109\end{array} \right.\) \(⇔\left[ \begin{array}{l}x=-91\\x=109\end{array} \right.\) Vậy `x=-91` hoặc `x=109` , `f,||x-5|-3|=9` `*TH_1:|x-5|-3=9` `⇔|x-5|=9+3` `⇔|x-5|=12` \(⇔\left[ \begin{array}{l}x-5=12\\x-5=-12\end{array} \right.\) \(⇔\left[ \begin{array}{l}x=12+5\\x=-12+5\end{array} \right.\) \(⇔\left[ \begin{array}{l}x=17\\x=-7\end{array} \right.\) `*TH_2:|x-5|-3=-9` `⇔|x-5|=-9+3` `⇔|x-5|=-6` ( Vô lý) Vậy `x=17` hoặc `x=-7` Bình luận
17+x-(352-400)=-32 17+x-(-48)=-32 x-(-48)=-32-17 x-(-48)=-49 x = -49 + (-48) x = -97 2130-(x+130)+72=-64 2130-(x+130)= -64 -74 2130-(x+130)=-138 (x+130)= 2130 – (-138) (x+130)= 2268 x = 2268 – 130 x = 2138 /x/-5=-1 Th1 : x – 5 = -1 x = -1 + 5 x = 4 Th2 : x – 5 = 1 x = 1 + 5 x = 6 Vậy x = {4;6} /x+2/-13=-1 /x+2/= -1 + 13 /x+2/ = 12 Th1 : x + 2 = 12 x = 12 -2 x = 10 Th2 : x+2 = -12 x= -12 – 2 x = -14 Vậy x={-14;10} 135-/9-x/=35 /9-x/= 135 – 35 /9-x/= 100 Th1 : 9 – x = 100 x = 9 – 100 x = -91 Th2 : 9 -x = -100 x = 9 -(-100) x = 109 Vậy x = {109;(-91)} Bình luận
Đáp án:
,
Giải thích các bước giải:
`a,17+x-(352-400)=-32`
`⇔x-(-48)=-32-17`
`⇔x+48=-49`
`⇔x=-49-48`
`⇔x=-97`
Vậy `x=-97`
,
`b,2130-(x+130)+72=-64`
`⇔2130-x-130+72=-64`
`⇔-x=-64-2130+130-72`
`⇔-x=-2136`
`⇔x=2136`
Vậy `x=2136`
,
`c,|x|-5=-1`
`⇔|x|=-1+5`
`⇔|x|=4`
\(⇔\left[ \begin{array}{l}x=4\\x=-4\end{array} \right.\)
Vậy `x=4` hoặc `x=-4`
,
`d,|x+2|-13=-1`
`⇔|x+2|=-1+13`
`⇔|x+2|=12`
\(⇔\left[ \begin{array}{l}x+2=12\\x+2=-12\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=12-2\\x=-12-2\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=10\\x=-14\end{array} \right.\)
Vậy `x=10` hoặc `x=-14`
,
`e,135-|9-x|=35`
`⇔|9-x|=135-35`
`⇔|9-x|=100`
\(⇔\left[ \begin{array}{l}9-x=100\\9-x=-100\end{array} \right.\)
\(⇔\left[ \begin{array}{l}-x=100-9\\-x=-100-9\end{array} \right.\)
\(⇔\left[ \begin{array}{l}-x=91\\-x=-109\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-91\\x=109\end{array} \right.\)
Vậy `x=-91` hoặc `x=109`
,
`f,||x-5|-3|=9`
`*TH_1:|x-5|-3=9`
`⇔|x-5|=9+3`
`⇔|x-5|=12`
\(⇔\left[ \begin{array}{l}x-5=12\\x-5=-12\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=12+5\\x=-12+5\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=17\\x=-7\end{array} \right.\)
`*TH_2:|x-5|-3=-9`
`⇔|x-5|=-9+3`
`⇔|x-5|=-6` ( Vô lý)
Vậy `x=17` hoặc `x=-7`
17+x-(352-400)=-32
17+x-(-48)=-32
x-(-48)=-32-17
x-(-48)=-49
x = -49 + (-48)
x = -97
2130-(x+130)+72=-64
2130-(x+130)= -64 -74
2130-(x+130)=-138
(x+130)= 2130 – (-138)
(x+130)= 2268
x = 2268 – 130
x = 2138
/x/-5=-1
Th1 : x – 5 = -1
x = -1 + 5
x = 4
Th2 : x – 5 = 1
x = 1 + 5
x = 6
Vậy x = {4;6}
/x+2/-13=-1
/x+2/= -1 + 13
/x+2/ = 12
Th1 : x + 2 = 12
x = 12 -2
x = 10
Th2 : x+2 = -12
x= -12 – 2
x = -14
Vậy x={-14;10}
135-/9-x/=35
/9-x/= 135 – 35
/9-x/= 100
Th1 : 9 – x = 100
x = 9 – 100
x = -91
Th2 : 9 -x = -100
x = 9 -(-100)
x = 109
Vậy x = {109;(-91)}