17,58×43+57×17,58
43,57×2,6x(630-315×2)
45×16-17 phần 45x 15+28
Tìm x
X/2+3/4=6/7
33,3:(x-3,5)+45,7=799
(X-1)+(X-2)+(X-3)+(X-4)=30
17,58×43+57×17,58 43,57×2,6x(630-315×2) 45×16-17 phần 45x 15+28 Tìm x X/2+3/4=6/7 33,3:(x-3,5)+45,7=799 (X-1)+(X-2)+(X-3)+(X-4)=30
By Ivy
Câu 1:
$\text{a) 17,58 × 43 + 57 × 17,58}$
$\text{= 17,58 × (43 + 57)}$
$\text{= 17,58 × 100}$
$\text{= 1758}$
$\text{b) 43,57 × 2,6 × (630 – 315 × 2)}$
$\text{= 43,57 × 2,6 × 0}$
$\text{= 0}$
c) $\dfrac{45 × 16 – 17}{45 × 15 + 28}$
$=\dfrac{45 × 15 + 45 – 17}{45 × 15 + 28}$
$\text{= 1}$
Câu 2:
a) $\dfrac{x}{2}$ + $\dfrac{3}{4}=$ $\dfrac{6}{7}$
$\dfrac{x}{2}=$ $\dfrac{6}{7}-$ $\dfrac{3}{4}$
$\dfrac{x}{2}=$ $\dfrac{3}{28}$
$\text{x=}$ $\dfrac{3}{28}$ $\text{× 2}$
$\text{x=}$ $\dfrac{3}{14}$
b)$\text{33,3 : (x – 3,5)+ 45,7 = 799}$
$\text{33,3 : (x – 3,5) = 799 – 45,7}$
$\text{33,3 : (x – 3,5) = 753,3}$
$\text{x – 3,5 = 33,3 : 753,3}$
$\text{x – 3,5 =}$ $\dfrac{37}{837}$
$\text{x =}$ $\dfrac{37}{837}$ $\text{+ 3,5}$
$\text{x =}$ $\dfrac{5933}{1674}$
c) $\text{(x – 1) + (x – 2) + (x – 3) + (x – 4) = 30}$
$\text{x – 1 + x – 2 + x – 3 + x – 4 = 30}$
$\text{4x – 10 = 30}$
$\text{4x = 30 + 10}$
$\text{4x = 40}$
$\text{x = 40 : 4}$
$\text{x = 10}$
$1) 17,58×43+57×17,58$
$⇒17,58×(43+57)$
$⇒17,58×100$
$⇒1758$
$2) 43,57×2,6×(630-315×2)$
$⇒43,57×2,6×0$
$⇒0$
$\text{3) $\dfrac{45×16-17}{45×15+28}$}$
$\text{⇒$\dfrac{45×15+45-17}{45×15+28}$}$
$\text{⇒$\dfrac{45×15+28}{45×15+28}$}$
$⇒1$
$\text{4) $\dfrac{x}{2}$+ $\dfrac{3}{4}$= $\dfrac{6}{7}$}$
$\text{⇒$\dfrac{x}{2}$= $\dfrac{3}{28}$}$
$⇒x×28=6$
$\text{⇒x=$\dfrac{3}{14}$}$
$5) 33,3÷(x-3,5)+45,7=799$
$⇒33,3÷(x-3,5)=753,3$
$⇒x-3,5=33,3÷753,3$
$\text{⇒x-3,5=$\dfrac{37}{837}$}$
$\text{⇒x=$\dfrac{37}{837}$+3,5}$
$\text{⇒x= $\dfrac{5933}{1674}$}$
$6) (x-1)+(x-2)+(x-3)+(x-4)=30$
$⇒x-1+x-2+x-3+x-4=30$
$⇒4x-10=30$
$⇒4x=40$
$⇒x=10$