17,58×43+57×17,58 43,57×2,6x(630-315×2) 45×16-17 phần 45×15+28 Tìm x X/2+3/4=6/7 33,3:(X-3,5)+45,7=799 (X-1)+(X-2)+(X-3)+(X-4)=30

0 bình luận về “17,58×43+57×17,58 43,57×2,6x(630-315×2) 45×16-17 phần 45×15+28 Tìm x X/2+3/4=6/7 33,3:(X-3,5)+45,7=799 (X-1)+(X-2)+(X-3)+(X-4)=30”

1. 17,58×43+57×17,58=17,58x(43+57)=17,58×100=1758

   43,57×2,6x(630-315×2)=43,57×2,6×0=0

   $\frac{45×16-17}{45×15+28}$=$\frac{703}{703}$ =1

   Tìm x

   X/2+3/4=6/7

   <=>(14 x X)/28+(3×7)/28=(6×4)/28

   <=>14 x X+21=24

   <=>14 x X=3

   <=>X=3/14

   33,3:(X-3,5)+45,7=799

   <=>33,3:(X-3,5)=799-45,7=753,3

   <=>X-3,5=753,3/33,3=22,62

   <=>X=26,12

   (X-1)+(X-2)+(X-3)+(X-4)=30

   <=>X-1+X-2+X-3+X-4=30

   <=>4 x X + 10=30

   <=>4 x X=40

   <=>X=10

    

   Trả lời

2. $B1:$

   $17,58×43+57×17,58$

   $=17,58×(43+57)$

   $=1758$

   $43,57×2,6×(630-315×2)$

   $=43,57×2,6×(630-630)$

   $=43,57×2,6×0$

   $=43,57×0$

   $=0$

   $45×16- 17/45 ×15+28$

   $=(45×16)-(17/45×15)+28$

   $=720-5+28$

   $=715+28$

   $=743$

   $B2:$

   x:2+ $\frac{3}{4}$ =$\frac{6}{7}$ 

   x:2  =$\frac{6}{7}$ -$\frac{3}{4}$ 

   x:2  =$\frac{3}{28}$ 

   x     =$\frac{3}{28}$ ×2

   x     =$\frac{3}{14}$ 

   $33,3:(x-3,5)+45,7=799$

   $33,3:(x-3,5)  =799-45,7$

   $33,3:(x-3,5)  =753,3$

           $x-3,5   =33,3:753,3$

           $x-3,5   =37/837$

   $(x-1)+(x-2)+(x-3)+(x-4)=30$

   $x-1+x-2+x-3+x-4=30$

   $4x + 10=30$

   $4x=40$

   $x=10$

   Trả lời