19/20 x (1/10 + 4/5 x (1 + y) – 3/20) = y tìm y 08/07/2021 Bởi Gianna 19/20 x (1/10 + 4/5 x (1 + y) – 3/20) = y tìm y
`19/20 × (1/10 + 4/5 × (1 + y) – 3/20) = y` `=> 19/20 × (1/10 + 4/5 + 4/5y – 3/20) = y` `=> 19/20 × (1/10 + 4/5 + 4/5y – 3/20) = y` `=> 19/20 × (9/10 + 4/5y – 3/20) = y` `=> 19/20 × (3/4 + 4/5y) = y` `=> 57/80 + 19/25y = y` `=> 57/80 + 19/25y – y = 0` `=> y(19/25 – 1) = -57/80` `=> -6/25y = -57/80` `=> y = 95/32` (Chúc bạn học tốt) Bình luận
Đáp án:
Giải thích các bước giải:
`19/20 × (1/10 + 4/5 × (1 + y) – 3/20) = y`
`=> 19/20 × (1/10 + 4/5 + 4/5y – 3/20) = y`
`=> 19/20 × (1/10 + 4/5 + 4/5y – 3/20) = y`
`=> 19/20 × (9/10 + 4/5y – 3/20) = y`
`=> 19/20 × (3/4 + 4/5y) = y`
`=> 57/80 + 19/25y = y`
`=> 57/80 + 19/25y – y = 0`
`=> y(19/25 – 1) = -57/80`
`=> -6/25y = -57/80`
`=> y = 95/32`
(Chúc bạn học tốt)