( √x-x+2/ √x+1)/(1/ √x+1-2/x-1) a, rút gọn b,tìm x để P=1/2 17/08/2021 Bởi Iris ( √x-x+2/ √x+1)/(1/ √x+1-2/x-1) a, rút gọn b,tìm x để P=1/2
a) ( √x-x+2/ √x+1)/(1/ √x+1-2/x-1)=-(√2 .x-√2)/2 b) P=1/2 ⇔ -(√2 .x-√2)/2=1/2 ⇔ -(√2 .x-√2) =1 ⇔ -√2.x +√2 =1 ⇔ -√2.x =1-√2 ⇔ x = -(1-√2)/√2 ⇔ x = (2-√2)/2 Xin ctl hay nhất Bình luận
a) ( √x-x+2/ √x+1)/(1/ √x+1-2/x-1)=-(√2 .x-√2)/2 b) P=1/2 ⇔ -(√2 .x-√2)/2=1/2 ⇔-(√2 .x-√2) =1 ⇔-√2.x +√2 =1 ⇔-√2.x =1-√2 ⇔x = -(1-√2)/√2 ⇔x = (2-√2)/2 Bình luận
a) ( √x-x+2/ √x+1)/(1/ √x+1-2/x-1)=-(√2 .x-√2)/2
b) P=1/2 ⇔ -(√2 .x-√2)/2=1/2
⇔ -(√2 .x-√2) =1
⇔ -√2.x +√2 =1
⇔ -√2.x =1-√2
⇔ x = -(1-√2)/√2
⇔ x = (2-√2)/2
Xin ctl hay nhất
a) ( √x-x+2/ √x+1)/(1/ √x+1-2/x-1)=-(√2 .x-√2)/2
b) P=1/2 ⇔ -(√2 .x-√2)/2=1/2
⇔-(√2 .x-√2) =1
⇔-√2.x +√2 =1
⇔-√2.x =1-√2
⇔x = -(1-√2)/√2
⇔x = (2-√2)/2