Toán |2x-1|-1/2=1/3. giải giúp mk với ???????????????? 23/07/2021 By Melody |2x-1|-1/2=1/3. giải giúp mk với ????????????????
|2x-1|=1/3+1/2⇔|2x-1|=5/6 ⇔\(\left[ \begin{array}{l}2x-1=5/6\\2x-1=-5/6\end{array} \right.\) ⇔\(\left[ \begin{array}{l}2x=11/6\\2x=1/6\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=11/12\\x=1/12\end{array} \right.\) Trả lời
$|2x-1|-$$\frac{1}{2}=$ $\frac{1}{3}$ $=>|2x-1|=$$ $$\frac{1}{3}+$$\frac{1}{2}$ $=>|2x-1|=$$\frac{5}{6}$ $=>$\(\left[ \begin{array}{l}2x-1=5/6\\2x-1=-5/6\end{array} \right.\) =>\(\left[ \begin{array}{l}2x=11/6\\2x=1/6\end{array} \right.\) =>\(\left[ \begin{array}{l}11/12\\x=1/12\end{array} \right.\) Vậy x=11/12 và x/1/12 Trả lời
|2x-1|=1/3+1/2⇔|2x-1|=5/6
⇔\(\left[ \begin{array}{l}2x-1=5/6\\2x-1=-5/6\end{array} \right.\)
⇔\(\left[ \begin{array}{l}2x=11/6\\2x=1/6\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=11/12\\x=1/12\end{array} \right.\)
$|2x-1|-$$\frac{1}{2}=$ $\frac{1}{3}$
$=>|2x-1|=$$ $$\frac{1}{3}+$$\frac{1}{2}$
$=>|2x-1|=$$\frac{5}{6}$
$=>$\(\left[ \begin{array}{l}2x-1=5/6\\2x-1=-5/6\end{array} \right.\) =>\(\left[ \begin{array}{l}2x=11/6\\2x=1/6\end{array} \right.\) =>\(\left[ \begin{array}{l}11/12\\x=1/12\end{array} \right.\)
Vậy x=11/12 và x/1/12