2/ x+1 – 1/ x-2 = 3x-11/(x+1)*(x-2) giải hộ mk nha mn

$\frac{2}{x+1}-\frac{1}{x-2}=\frac{3x-11}{(x+1)(x-2)}$  $Đkxđ:x\neq-1,x\neq2$

$⇒2x-4-x-1=3x-11$

$⇔-2x=-6$

$⇔x=3$ $(tm$ $đkxđ)$

Vậy $S=${$3$}.