Toán / 2x – 1 phần 3 / + 5 phần 6 = 1: Tìm x 07/10/2021 By Eden / 2x – 1 phần 3 / + 5 phần 6 = 1: Tìm x
/(2x-1)/3/+5/6=1 /(2x-1)/3)=1-5/6=1/6 TH1:(2x-1)/3=1/6 2x-1=1/6.3=1/2 2x=1/2+1=3/2 x=3/2:2=3/4 TH2:(2x-1)/3=-1/6 2x-1=-1/6.3=-1/2 2x=-1/2+1=1/2 x=1/2:2=1/4 Vậy x=3/4,x=1/4 CHÚC BẠN HỌC TỐT Trả lời
($2x^{}$ – $\frac{1}{3}$) + $\frac{5}{6}$ = $1^{}$ ($2x^{}$ – $\frac{1}{3}$)= $1^{}$ – $\frac{5}{6}$ ($2x^{}$ – $\frac{1}{3}$)= $\frac{1}{6}$ $2x^{}$= $\frac{1}{6}$ – $\frac{1}{3}$) $2x^{}$ = $\frac{1}{2}$ ⇒ x=$\frac{1}{4}$ Trả lời
/(2x-1)/3/+5/6=1
/(2x-1)/3)=1-5/6=1/6
TH1:(2x-1)/3=1/6
2x-1=1/6.3=1/2
2x=1/2+1=3/2
x=3/2:2=3/4
TH2:(2x-1)/3=-1/6
2x-1=-1/6.3=-1/2
2x=-1/2+1=1/2
x=1/2:2=1/4
Vậy x=3/4,x=1/4
CHÚC BẠN HỌC TỐT
($2x^{}$ – $\frac{1}{3}$) + $\frac{5}{6}$ = $1^{}$
($2x^{}$ – $\frac{1}{3}$)= $1^{}$ – $\frac{5}{6}$
($2x^{}$ – $\frac{1}{3}$)= $\frac{1}{6}$
$2x^{}$= $\frac{1}{6}$ – $\frac{1}{3}$)
$2x^{}$ = $\frac{1}{2}$
⇒ x=$\frac{1}{4}$