/x-2/-12=-1 135-/9-x/=35 (1-3x).(x+2)=0 3x-10=2x+13 14+4x=3x+20 (x+2).(3-x)=0

0 bình luận về “/x-2/-12=-1 135-/9-x/=35 (1-3x).(x+2)=0 3x-10=2x+13 14+4x=3x+20 (x+2).(3-x)=0”

1. `\text{~~Holi~~}`

   `|x-2|-12=-1`

   `-> |x-2|=11`

   `->`\(\left[ \begin{array}{l}x-2=11\\x-2=-11\end{array} \right.\) 

   `->`\(\left[ \begin{array}{l}x=13\\x=-9\end{array} \right.\) 

   Vậy `x_1=13, x_2=-9`

   ______________

   `135-|9-x|=35`

   `-> |9-x|=100`

   `->`\(\left[ \begin{array}{l}9-x=100\\9-x=-100\end{array} \right.\) 

   `->`\(\left[ \begin{array}{l}x=-91\\x=109\end{array} \right.\) 

   Vậy `x_1=-91, x_2=109`

   ______________

   `(1-3x)(x+2)=0`

   `->`\(\left[ \begin{array}{l}1-3x=0\\x+2=0\end{array} \right.\) 

   `->`\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=-2\end{array} \right.\) 

   Vậy `x_1=1/3, x_2=-2`

   ______________

   `3x-10=2x+13`

   `-> 3x-2x=13+10`

   `-> x=23`

   Vậy `x=23`

   ______________

   `14+4x=3x+20`

   `-> 4x-3x=20-14`

   `-> x=6`

   Vậy `x=6`

   ______________

   `(x+2)(3-x)=0`

   `->`\(\left[ \begin{array}{l}x+2=0\\3-x=0\end{array} \right.\) 

   `->`\(\left[ \begin{array}{l}x=-2\\x=3\end{array} \right.\) 

   Vậy `x_1=-2, x_2=3`

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2. Câu `1` :

   `|x- 2| – 12 = -1`

   `|x – 2| = 11`

   `⇒ ` `x – 2 = 11` hoặc `x – 2 = -11`

   `⇒ x = 13` hoặc `x = -9`

   Câu `2` :

   `135 – |9 – x| = 35`

   `|9 – x| = 100`

   `⇒ 9 – x = 100` hoặc `9 -x = -100`

   `⇒ x = – 91` hoặc `x = 109`

   Câu `3` :

   `(1 – 3x)(x +2 ) =  0`

   `1 – 3x = 0` hoặc `x + 2 = 0`

   `x = 1/3` hoặc `x = -2`

   Câu `4 ` :

   `3x – 10 = 2x + 13`

   `3x – 2x = 13 +10`

   `x = 23`

   Câu `5` :

   `14 + 4x = 3x + 20`

   `4x – 3x = 20 – 14`

   `x = 6`

   Câu `6`

   `(x+2)(3-x) = 0`

   `x+2 =  0` hoặc `3 – x = 0`

   ` x = -2` hoặc `x = 3`

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